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sergiy2304 [10]
3 years ago
14

If 13 candy bars cost $21.97, how much do 20 candy bars cost?

Mathematics
1 answer:
Paul [167]3 years ago
5 0
Answer: $33.80

Step 1: Find out the cost for one candy bar

To find out the cost for one candy bar, you will need to divide $21.97 by 13. Another way to say this would be by rewriting the equation as 13x=21.97. After dividing, you see that one candy bar is $1.69.

Step 2: Find out the cost for 20 candy bars

To figure out the cost of 20 candy bars, simply multiply the price for one by 20. Another way to say this would be by rewriting this as 1.69x20=33.8.

Step 3: Your answer!

By completing the above steps, you have figured out the answer of $33.80.

Hope this helps!
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Using the following relations:

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Underage drinking, Part I: Data collected by the Substance Abuse and Mental Health Services Administration (SAMSHA) suggests tha
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Answer:

a. <u>Yes, there are 10 independent trials, each with exactly two possible outcomes, and a constant probability associated with each possible outcome.</u>

b. <u>The probability is 0.2029 or 20.29%</u>

c. <u>The probability is 0.2029 or 20.29%</u>

d. <u>The probability is 0.1671 or 16.71%</u>

e. <u>The probability is 0.9975 or 99.75%</u>

Step-by-step explanation:

<u>a. Yes, there are 10 independent trials, each with exactly two possible outcomes, and a constant probability associated with each possible outcome.</u>

b. Let's use the binomial distribution table, this way:

Binomial distribution (n=10, p=0.697)

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x Pr[X = x] Pr[X ≤ x]

0 0.0000 0.0000

1 0.0002 0.0002

2 0.0016 0.0017

3 0.0095 0.0112

4 0.0384 0.0496

5 0.1059 0.1555

6 <u>0.2029</u> 0.3584

7 0.2668 0.6252

8 0.2301 0.8553

9 0.1176 0.9729

10 0.0271 1.0000

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c. If 69.7% of 18-20 years old consumed alcoholic beverages in 2008, therefore, 30.3% did not and the binomial distribution table is:

Binomial distribution (n=10, p=0.303)

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x Pr[X = x] Pr[X ≤ x]

0 0.0271 0.0271

1 0.1176 0.1447

2 0.2301 0.3748

3 0.2668 0.6416

4 <u>0.2029</u> 0.8445

5 0.1059 0.9504

6 0.0384 0.9888

7 0.0095 0.9983

8 0.0016 0.9998

9 0.0002 1.0000

10 0.0000 1.0000

<u>The probability is 0.2029 or 20.29%</u>

d. Let's use the binomial distribution table, this way:

Binomial distribution (n=5, p=0.697)

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x Pr[X = x] Pr[X ≤ x]

0 0.0026 0.0026

1 0.0294 0.0319

2 0.1351 <u>0.1671 </u>

3 0.3109 0.4779

4 0.3576 0.8355

5 0.1645 1.0000

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<u>The probability is 0.1671 or 16.71%</u>

e. Using the same binomial distribution table we used in d. we have:

P(1) + P (2) + P(3) + P(4) + P (5) = 0.0294 + 0.1351 + 0.3109 + 0.3576 + 0.1645

<u>The probability is 0.9975 or 99.75%</u>

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Answer:

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Step-by-step explanation:

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~

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