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3 years ago

Reasoning can you name a real number that is represented by √-36? Explain

Mathematics

2 answers:

jekas [21]3 years ago

8 0

Your question has been heard loud and clear

√-36 is by no means a real number. This is because square roots can only be positive in nature.

Eg: -2*-2 = 4 and 2*2 = 4 , so √4 = -2 or 2 but √-4 doesnt exist.

So , √-36 also does not exist while √36 exists.

√-36 , we can however represent it as an imaginary number as 36i

Thank you

alex41 [277]3 years ago

4 0

Square root of - does not exist in the set of real numbers

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zavuch27 [327]

Answer:

Step-by-step explanation:

240

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3 years ago

(6x10^2)/(3x10-5) help what is this in standard form?

Tasya [4]

Answer:

The standard form of $\frac{6 \times 10^{2}}{3 \times 10^{-5}}$ is 20,00,0000

Solution:

Given that $\frac{6 \times 10^{2}}{3 \times 10^{-5}}$ ---- eqn 1

To write $\frac{6 \times 10^{2}}{3 \times 10^{-5}}$ in standard form,

We know that $\bold{\frac{1}{a^{-m}} = a^{m}}$ .So $\frac{1}{10^{-5}}$ becomes $10^{5}$ .

Now eqn 1 becomes,

$= \frac{6 \times 10^{2}}{3} \times 10^{5}$ ----- eqn 2

We know that $\bold{a^{m} \times a^{n}=a^{m+n}}$ , so $10^{2} \times 10^{5} = 10^{7}$

Now eqn 2 becomes,

$= \frac{6}{3} \times 10^{7}$

$= 2 \times 10^{7}$ ---- eqn 3

Expanding $10^{7}$ :

Here 10 is the base term and 7 is the exponent value. So base term 10 is multiplied by itself 7 times.

$10^{7} = 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10$

Now eqn 3 becomes,

$= 2 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10$

= 20,00,0000

Hence the standard form of $\frac{6 \times 10^{2}}{3 \times 10^{-5}}$ is 20,00,0000

6 0

3 years ago

Reduce to simplest form. -5/8+(-8/5)=?

lara31 [8.8K]

Answer:

$-2\frac{9}{40}$

Step-by-step explanation:

$-\frac{5}{8}+(-\frac{8}{5}) = -\frac{25}{40}-\frac{64}{40}$ (find common denominator)

$=-\frac{89}{40}$

$=-2\frac{9}{40}$ (reduce to simplest form)

Hope this helps :)

4 0

2 years ago

What is 5 3/4 as a decimal?

ziro4ka [17]

Answer:

5.75

Step-by-step explanation:

$5 \frac{3}{4} = \frac{5 \times 4 + 3}{4} = \frac{20 + 3}{4} = \frac{23}{4} = 5.75 \\$

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3 years ago

Solve the system by substitution 5x+y=-10. 4x-7y=-8

storchak [24]

Answer:

x = -2 and y = 0

Step-by-step explanation:

5x + y = -10

4x - 7y = -8

Rearrange the first equation to equal y.

5x + y = -10

y = -10 - 5x

Replace y in the second equation with the first equation.

4x - 7y = -8

4x - 7(-10 - 5x) = -8

4x - (-70 -35x) = -8

4x + 70 + 35x = -8

Rearrange the equation to find x.

4x + 35x = -8 - 70

39x = -78

x = -2

Now that you know x, use the rearranged first equation to find y.

y = -10 - 5x

y = -10 - 5(-2)

y = -10 + 10

y = 0

8 0

3 years ago