Cot= cos/sin
<=> cot= [(✔️13^2-5^2)/13]/(5/13)
<=> cot= (12/13)/(5/13)
<=> cot= 12/5
Answer:
<h3>0.2</h3>
Step-by-step explanation:
Given a linear function f(x) that varies at a constant rate of change 1.5 with respect to x, If x varies from x = 1.3 to x = 1.5, the to get the amount by which x change by, we will use the expression;
Δx = x₂-x₁
x₂ is the final value of x
x₁ is the initial value of x
Given x₁ = 1.3 and x₂ = 1.5
Substitute the values in the formula above;
Δx = x₂-x₁
Δx = 1.5 - 1.3
Δx = 0.2
Hence the value of x change by 0.2
10x + 2y = -2
2y = -10x - 2
y = -(10/2)x - 2/2
y = -5x - 1 y = mx + c, slope m = -5.
If it is parallel, then the slope of the second line ought to be -5 as well.
So you should fill -5 in the bracket.
Answer:
the slope is "1"
the y-intercept is "5"
y = x + 5
Step-by-step explanation:
In order to find the slope, we use the slope formula with any pair of points, for example: (1, 6) and (3, 8):
slope = (y2-y1) / (x2 - x1)
in our case:
slope = (8 - 6) / (3 - 1) = 2/2 = 1
then the slope is "1".
Now we write the general "slope-intercept" equation of a line using the slope we found:
y = m x + b
y = 1 x + b
and now use one of the points (for example (3, 8) to find the intercept "b":
(8) = 1 (3) + b
8 - 3 = b
b = 5 (y intercept)
Then the equation of the line can be written as:
y = x + 5
