Answer:
Surface area of square pyramid is computed as follows:
A = a² + a*√(a² + 4h²)
where <em>a</em> is the base length and <em>h</em> is the height.
If a model of the square pyramid is scaled down by a factor of x, then the surface area will be:
A' = (a/x)² + (a/x)*√[(a/x)² + 4(h/x)²]
A' = a²/x² + a/x * √[a²/x² + 4h²/x²]
A' = a²/x² + a/x * √[(a² + 4h²)/x²]
A' = a²/x² + a/x * √(a² + 4h²)/√x²
A' = a²/x² + a/x² * √(a² + 4h²)
A' = 1/x² * [a² + a*√(a² + 4h²)]
A' = 1/x² * A
That is, the surface area will be 1/x² times the original surface area. If h = 25 ft and a = 15 ft:
A = 15² + 15*√(15² + 4(25)²) = 1008.02 ft²
The factor is not mentioned in the question, nevertheless, the area will be 1008.02/factor² ft²
D is distance.
<span>d/2 + d/4 = 6 </span>
<span>3d/4 = 6 </span>
<span>d = 8 km </span>
<span>Check: at 2 k/h, 4 hours; </span>
<span>at 4 k/h, 2 hours; </span>
<span>total, 6 hours. hope i helped</span>
Answer:
- 5/13
Step-by-step explanation:
tans = 5/12 = height/base
Using Pythagoras, hypotenuse = √12² + 5² = 13
Therefore coss had to be 12/13
But since cos s < 0, cos s = - 12/13
Thus,
tanA = sinA/cosA
tanA cosA = sinA
(5/12)(- 12/13) = sinA
- 5/13 = sinA
Answer:
it would be (1,-3) because those point are in the shaded region. therefore it is a solution
Step-by-step explanation:
I believe the answer is B for this question