Question

Which is closest to the height of a cone that has a slant height of 16 inches and a radius of 6 inches?

Answer 1

$l \: = \sqrt{h ^{2} \: + \: r^2 }$
$h = \sqrt{l^{2} - {r}^{2} }$
Given
l (slant height) = 16 inches
r (radius) = 6 inches
$h = \sqrt{ {16}^{2} - {6}^{2} }$
$h = \sqrt{256 - 36}$
$h = \sqrt{220}$
h = 14.832 inches

Answer 2

Answer: 14.83 inches

Explanation:

h² + 6² = 16²

h² = 16² - 6²

h² = 220

h = 14.83