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ella [17]
3 years ago
12

If the length of a flag is 18 inches and the width is 12 inches what is the area

Mathematics
2 answers:
attashe74 [19]3 years ago
8 0

Answer:

18 by 12 is 216

Serjik [45]3 years ago
6 0

Answer:

216

Step-by-step explanation:

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Show work!!!!!!!!!!!!!!
kipiarov [429]

Answer:

147

Step-by-step explanation:

you just add both angles

5 0
3 years ago
Suppose μ1 and μ2 are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of bra
Stella [2.4K]

Answer:

The 95% confidence interval would be given by -23.44 \leq \mu_1 -\mu_2 \leq -8.16  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =114.1 represent the sample mean 1

\bar X_2 =129.9 represent the sample mean 2

n1=5 represent the sample 1 size  

n2=2 represent the sample 2 size  

s_1 =5.08 sample standard deviation for sample 1

s_2 =5.37 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

Confidence interval

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =114.1-129.9=-15.8

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n_1 +n_2 -1=5+5-2=8  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that t_{\alpha/2}=\pm 2.31  

The standard error is given by the following formula:

SE=\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=3.306

Confidence interval

Now we have everything in order to replace into formula (1):  

-15.8-2.31\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=-23.437  

-15.8+2.31\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=-8.163  

So on this case the 95% confidence interval would be given by -23.44 \leq \mu_1 -\mu_2 \leq -8.16  

8 0
3 years ago
Solve the inequality
Sergeu [11.5K]

Answer:

C. x > 35

Step-by-step explanation:

X+11>46

X>46

   -11

X>35

5 0
3 years ago
This is a re-write I forgot to add the picture. Math Review. Help need ASAP please!!
Lena [83]
1. 78
2. 3

Please make sure to put the correct measurement letters too.
6 0
3 years ago
PRETTY PLEASE HELP!! ILL GIVE BRAINLIEST! it’s due tonight :(
Marianna [84]

Answer:

a = 8 m

Step-by-step explanation:

Since, given is an isosceles right triangle.

So, by Pythagoras theorem:

{a}^{2}  +  {a}^{2}  =  {(8 \sqrt{2} )}^{2}  \\  \\ 2 {a}^{2}  = 128 \\  \\  {a}^{2}  =  \frac{128}{2}  \\  \\  {a}^{2}  = 64 \\  \\ a =  \sqrt{64}  \\  \\ a = 8 \: m

5 0
3 years ago
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