Answer:
2 real solutions
Step-by-step explanation:
We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:
b² - 4ac
If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.
Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:
b² - 4ac
(-20)² - 4 * 6 * 1 = 400 - 24 = 376
Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.
<em>~ an aesthetics lover</em>
X(x+1) 1(x+4)
x^2+x+x+4
x^2+2x+4
Answer:
x is 6 because
y is 30
p is 120
Step-by-step explanation:
60 degrees and 10x are the same and 6×10 = 60
(4y) and 60 degrees must equal 180 so y has to be 30
(4y) and p are the same
Answer:
p < -7
Step-by-step explanation:
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Answer: you don't insult someone when they are being nice to you i i cant even do that c:
Step-by-step explanation:
