Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
Answer:
x=4
Step-by-step explanation:
all you need to do is the 3rd root of 64
which is 4.
Answer:
Step-by-step explanation:
reduced
transformed the expression to make it easier
add
reduce
Answer:
2v+2
Step-by-step explanation:
Answer:
y= -54-2
y= -56 &
x= -54/ -9
x= 6
Step-by-step explanation:
y= -9x-2
-9x= y+2 divide bothe side by -9
x=y+2/-9
y= -9(y+2/ -9) -2 = (y+2)-2
y= -2(y+2)
y= -2y-4
y+2y= -4
3y= -4 divide bothe side by 3
y= -4/3
x=y+2/ -9
x= -4/3+2/-9
x= -2/3× -9
x=18/3
x=6
