Answer:
I think 5 and 7 I got that question
Answer:
So there are 500 pairs of numbers that have a sum of 1001. Thus, the sum of numbers from 1 to 1000 is 500*1001 = 500,500.
Step-by-step explanation:
Answer:
3.83
Step-by-step explanation:
Mean of x = Σx / n
Mean of x = (14 + 19 + 13 + 6 + 9) / 5 = 12.2
Sum of square (SS) :
(14-12.2)^2 + (19-12.2)^2 + (13-12.2)^2 + (6-12.2)^2 + (9-12.2)^2 = 98.8
Mean of y = Σy / n
Mean of y = (101 + 89 + 48 + 21 + 47) / 5 = 61.2
Σ(y - ybar)² = (101-61.2)^2 + (89-61.2)^2 + (48-61.2)^2 + (21-61.2)^2 + (47-61.2)^2 = 4348.8
df = n - 2 = 5 - 2 = 3
Σ(y - ybar)² / df = 4348.8 / 3 = 1449.6
√(Σ(y - ybar)² / df) = √1449.6 = 38.074
Standard Error = √(Σ(y - ybar)² / df) / √SS
Standard Error = 38.074 / √98.8
Standard Error = 3.83
First of all you have to make them equal to each other. What I mean is the following
3x+20=2x+40
Then you should just solve for x
After you hit the ball a couple of times or one big hit and just leave the ball bouncing
