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gizmo_the_mogwai [7]
3 years ago
10

Evaluate the expression 7+4b when b=3

Mathematics
1 answer:
Alex17521 [72]3 years ago
6 0

Answer:

19

Step-by-step explanation:

If we plug in b=3 then it would be 7+4(3), First we solve what 4 times 3 is which is 12 then we add 7+12 which is 19

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ANSWER ASAP GIVING BRAINLIEST FIVE STARS AND HEART!
Salsk061 [2.6K]

Answer:

Inches are not an appropriate unit of length for the distance from your home to school because it is a short unit of measurement and using feet or meters would be a better solution since feet and meters are both a longer unit of measurement and feet and meters would be a more accurate answer than inches.

Step-by-step explanation:

7 0
3 years ago
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Nadine bought the ingredients for 24 cupcakes for $5.60. She sold each cupcake for $1.30. She saved 25% of the profits and used
ololo11 [35]
The answer is C. 19.2
3 0
4 years ago
Suppose that 16 inches of wire costs 80 cents. At the same rate, how much in cents will 11 inches of wire cost
irga5000 [103]

Find the cost of 1 inch by dividing 80 cents by 16 inches, then multiply that cost by 11:


0.80 / 16 = 0.05 per inch.


11 inches x 0.05 = 0.55


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3 years ago
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(2x^3-5x^2+8)(x+3)=?
Alla [95]
(2x³ - 5x² + 8)(x + 3) = ?
First step is to distribute.

2x^4 + 6x³ - 5x³ - 15x² + 8x + 24
Now combine like terms.

2x^4 + x³ - 15x² + 8x + 24

This is your answer, since you can't simplify any further or solve it without some more information.
8 0
4 years ago
A person standing at the edge of a cliff throws a rock upward from a height of 180ft above ground level with an initial velocity
taurus [48]

Answer: 8.73 ft/s

Step-by-step explanation:

We have the following equation that models the motion of the rock:

h(t)=-16t^{2}+64t+180

Where h(t) is the height of the rock at a time t.

Now, if  h(t)=48 ft we can find t and then the velocity of the rock at that height:

48=-16t^{2}+64t+180

Rearranging the equation:

-16t^{2}+64t+132=0

Multiplying the equation by -1:

16t^{2}-64t-132=0

Solving with the quadratic formula t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}  , where a=16, b=-64, c=-132 .

t=\frac{-(-64)\pm\sqrt{(-64)^{2}-4(16)(-132)}}{2(16)}

Choosing the positive result of the equation:

t=5.5 s  

Since velocity V is defined as the traveled distance h(t) in a given time t, we have:

V=\frac{h(t)}{t}

V=\frac{48 ft}{5.5 s}

V=8.727 ft/s \approx 8.73 ft/s This is the velocity of the rock at the height of 48 feet

7 0
3 years ago
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