Answer:
P(A) = 86/100
P(B) = 79/100
P(A') = 14/100
P(A U B) = 95/100
P(A' U B) = 84/100
Step-by-step explanation:
i. P(A) = number of disks with high shock resistance/total number of disks
= (70+16)/100
= 86/100
ii. P(B) = number of disks with high scratch resistance/total number of disks
= (70+9)/100
= 79/100
iii. P(A') = number of disks without high shock resistance/total number of disks
= (100-86)/100
= 14/100
iv. P(AUB) = number of disks with high shock resistance or high scratch resistance/total number of disks
= (70+9+16)/100
= 95/100
v. P(A'UB) = number of disks without high shock resistance or with high scratch resistance/total number of disks
= (5+9+70)/100
= 84/100
Answer:
6/9
Step-by-step explanation:
Answer:
31.3%
Step-by-step explanation:
Start by doing the binomial expansion of (x+y)^6 where x represents success. This is
(x^6y^0) + 6(x^5y^1) +15(x^4y^2) +20(x^3y^3) +15(x^2y^4) +6(x^1y^5) +(x^0y^6)
We are interested in the x^3y^3 term which represents exactly 3 successes. Since the probability of success and failure are both .5 we should be able to figure this out just using the coefficients of the terms which is
20/64 = .3125 which is 31.25% Rounding yo the nearest tenth gives us
Answer:
Step-by-step explanation:
<u>Number of those drive to school:</u>
<u>Number of those don't drive:</u>
<u>Probability:</u>
- P(Drive to school ' ) = 60/100 = 3/5
Answer:
50 cents
Step-by-step explanation:
half of 5.00$ is 2.50$
