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Nitella [24]
2 years ago
12

Suppose the population of a town is 17,400 and is growing 2% each year.

Mathematics
2 answers:
sveticcg [70]2 years ago
8 0

Answer: 20,532

Step-by-step explanation:

17,400(.02)=348

348(9)=3132

17,400+3132=20,532

svet-max [94.6K]2 years ago
6 0

Answer:

Step-by-step explanation:

This is an exponential growth function of the form:

y=ab^x where a is the initial population and b is the growth rate. This could also be written as

y=a(1+r)^x which is a bit more accurate. We'll use that one. r is the percent growth: 2% for us.

Filling in the formula:

y=17400(1+.02)^x and then simplifying:

y=17400(1.02)^x

That's the model for this population. Filling in any number of years for x will give you the population y. Our time is 9 years:

y=17400(1.02)^9

Take care of the exponents first, giving us:

y=17400(1.195092569) and then multiply to get

y = 20,794.6 or 20,794 people (since you can't have 6/10 of a person)

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