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krek1111 [17]
3 years ago
13

What did I do wrong? I did the check but I didn’t get the same answer.

Mathematics
1 answer:
STatiana [176]3 years ago
3 0

Answer:

Solution = ( 0, 4 )

Step-by-step explanation:

You made one tiny error. When you were attempting to substitute your y value, 4, to derive the x - value, you took the second equation. However, that second equation was x + 2y = 8, when you substituted y as 4 you rewrote this equation as x + 2( 4 ) = 12, instead it should have been x + 2( 4 ) = 8!

If you would like, let me explain how to get the right answer;

x + 2 * ( 4 ) = 8,\\x + 8 = 8,\\x = 8 - 8 = 0\\\\x = 0, y = 4\\Solution = ( 0, 4 )

And as for your " check " let us substitute these values into both the equations, for true confirmation;

- 5 * ( 0 ) + 3 * ( 4 ) = 12,\\0 + 12 = 12,\\12 = 12\\Correct!\\\\0 + 2 * ( 4 ) = 8,\\0 + 8 = 8,\\8 = 8\\Correct!

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Use the absolute value formula to express the distance between 9 and -8
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Answer:

17

Step-by-step explanation:

| 9- (- 8) | = | 17 | = 17

Basically the absolute value of N1 - N2

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A value is in the domain if there is a ____ on the graph of the function at that x-value
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<span>A value is in the domain if there is a point on the graph of the function at that x-value</span>
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3 years ago
When k=7 and q=35 find the value of p in direct proportion method
Arisa [49]
I think the answer is 5.

y = kx is the equation for direct proportionality. I’m guessing your “q” is the “y”, because 35 is easily divisible by 7.

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2 years ago
Which expression has the fewest significant figures?
yanalaym [24]

Hello!

Here are some rules to determine the number of significant figures.

  1. Numbers that are not zero are significant (45 - all are sigfigs)
  2. Zeros between non-zero digits are significant (3006 → all are sigfigs)
  3. Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
  4. Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
  5. Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
  6. In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)

Now, let's find the number of significant figures in each given number.

A). 296.54

Since these digits are all <em>non-zero</em>, there are 5 significant figures.

B). 5003.1

Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.

C). 360.01

Again, the two zeros are between non-zero digits. There are 5 significant figures.

D). 18.3

All of these digits are non-zero, hence, there are 3 significant figures.

Therefore, expression D has the fewest number of significant figures being 3.  

4 0
3 years ago
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338.08=8(0.07m+28.90+.30(28.90)
AlladinOne [14]

Answer:

m= - 396.253089

Step-by-step explanation:

hope this helps

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2 years ago
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