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Diano4ka-milaya [45]
3 years ago
5

Jayden uses the net below to design a box.

Mathematics
1 answer:
Kryger [21]3 years ago
3 0
C) 128 ft²



The net consists of six parallelograms, each representing one face of the box.
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If a line slope of -1/2 contains the point (2,3), then it must also contain which of the following points?
tiny-mole [99]
Before the fraction: -1/2, i have a negative sign
use y=mx+b
3=-1/2(2)+b
3+1=-1+b+1
4=b
check your work
0=-1/2x+4
0+4=-1/2x
(4)÷(-1/2)=(-1/2x)÷(-1/2)
-2=x
another pair is (-2,0) use this to figure out the other points, and/or the points you have in the multiple choice.
5 0
4 years ago
What is the decimal equivalent for 1 5/27
grandymaker [24]

Answer: 1.18519

Step-by-step explanation:

1 5/27 = 32/27

= approximate value = 1.18519

5 0
3 years ago
What is the value of B for the following triangular prism?
Vika [28.1K]

Answer:

56cm is not the answer for sure trust me

Step-by-step explanation:

I took the test so dont worry!

5 0
4 years ago
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Use the X method to find the solutions of<br><br> 6x2 + 2x – 20 = 0.
Keith_Richards [23]

Answer:Hopes this helps!

6x²+2x-20=0

==>6x²+12x-10x-20=0

==>6x(x+2)-10(x+2)=0

==>(x+2)(6x-10)=0

==>x=-2 or x=5/3

5 0
3 years ago
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Complete the given diagram by dragging expressions to each leg of the triangle. Then, correctly complete the equation to derive
Nimfa-mama [501]

The equation to derive the distance d is \sqrt{(x2-x1)^2+(y2-y1)^2}. The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).

<h3>What is the formula for calculating the distance between two points?</h3>

Consider the two points (x1, y1) and (x2, y2)

The formula used for calculating the distance between the two points is

distance = \sqrt{(x2-x1)^2+(y2-y1)^2}

<h3>Calculation:</h3>

Given that,

The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)

Since this triangle makes 90°, it is a right-angled triangle.

Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).

Consider the length of the hypotenuse = d

So, using the distance formula, the length of the hypotenuse(d) is,

d = \sqrt{(x2-x1)^2+(y2-y1)^2}

And the lengths of the other two legs of the given triangle are,

Length of the adjacent side: (x1, y1) to (x2,y1)

= \sqrt{(x2-x1)^2+(y1-y1)^2}

= \sqrt{(x2-x1)^2+0}

= (x2-x1)

Length of the opposite side: (x2, y1) to (x2, y2)

= \sqrt{(x2-x2)^2+(y2-y1)^2}

= \sqrt{0+(y2-y1)^2}

= (y2-y1)

Therefore, the derived distances for the given triangle are:

d=\sqrt{(x2-x1)^2+(y2-y1)^2}, (x2 - x1), and (y2 - y1).

Learn more about the distance between two points here:

brainly.com/question/661229

#SPJ1

4 0
2 years ago
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