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TEA [102]
2 years ago
13

Match each expression with the equivalent expanded expression.

Mathematics
2 answers:
natulia [17]2 years ago
6 0
I got the same thing

1-1
2-3
3-5
4-2
5-4
erastova [34]2 years ago
3 0
1-1
2-3
3-5
4-2
5-4




Isjdjsh
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5*9 (sqrt 10)^3= Help please
Nikitich [7]
Use BODMAS or BIDMAS (Brackets, over Indices, Division, Multiplication, Addition, the Subtraction, this tells you which order to do things in)

As you cant do √10 in the brackets you do the indices, so (√10)³
Split this up to make it easier
(√10)³= √10 x √10 x √10 = 10√10

You the multiply this by 9

9 x 10√10 = 90√10

then multiply by 5

5 x 90√10 = 450√10 = 1423.024947 (using calculator)
7 0
2 years ago
Given the right triangle below, if AB = 4 and BC = 4, find AC.
Usimov [2.4K]

Answer:

squre root 32

Step-by-step explanation:

6 0
3 years ago
Someone please help !! I don’t know what I’m doing with this !!
dimulka [17.4K]

Answer:

  a) d(sinh(f(x)))/dx = cosh(f(x))·df(x)/dx

  b) d(cosh(f(x))/dx = sinh(f(x))·df(x)/dx

  c) d(tanh(f(x))/dx = sech(f(x))²·df(x)/dx

  d) d(sech(4x+2))/dx = -4sech(4x+2)tanh(4x+2)

Step-by-step explanation:

To do these, you need to be familiar with the derivatives of hyperbolic functions and with the chain rule.

The chain rule tells you that ...

  (f(g(x)))' = f'(g(x))g'(x) . . . . where the prime indicates the derivative

The attached table tells you the derivatives of the hyperbolic trig functions, so you can answer the first three easily.

__

a) sinh(u)' = sinh'(u)·u' = cosh(u)·u'

For u = f(x), this becomes ...

  sinh(f(x))' = cosh(f(x))·f'(x)

__

b) After the same pattern as in (a), ...

  cosh(f(x))' = sinh(f(x))·f'(x)

__

c) Similarly, ...

  tanh(f(x))' = sech(f(x))²·f'(x)

__

d) For this one, we need the derivative of sech(x) = 1/cosh(x). The power rule applies, so we have ...

  sech(x)' = (cosh(x)^-1)' = -1/cosh(x)²·cosh'(x) = -sinh(x)/cosh(x)²

  sech(x)' = -sech(x)·tanh(x) . . . . . basic formula

Now, we will use this as above.

  sech(4x+2)' = -sech(4x+2)·tanh(4x+2)·(4x+2)'

  sech(4x+2)' = -4·sech(4x+2)·tanh(4x+2)

_____

Here we have used the "prime" notation rather than d( )/dx to indicate the derivative with respect to x. You need to use the notation expected by your grader.

__

<em>Additional comment on notation</em>

Some places we have used fun(x)' and others we have used fun'(x). These are essentially interchangeable when the argument is x. When the argument is some function of x, we mean fun(u)' to be the derivative of the function after it has been evaluated with u as an argument. We mean fun'(u) to be the derivative of the function, which is then evaluated with u as an argument. This distinction makes it possible to write the chain rule as ...

  f(u)' = f'(u)u'

without getting involved in infinite recursion.

7 0
2 years ago
Someone please help me ASAP
IRISSAK [1]

Answer:

-4, -3, -2, -1, 0, and 1

Step-by-step explanation:

-2<n+3<=4

-2<n+3<5

subtracting, we get:

-5<n<2

So the possible values of n are -4, -3, -2, -1, 0, and 1.

4 0
2 years ago
Read 2 more answers
3x(x+3)=5x+4 solve the equation
max2010maxim [7]
<span>3x(x+3)=5x+4
3x+9x=5x+4
12x=5x+4
12x-5x=4
7x=4
x=0.57</span>
3 0
3 years ago
Read 2 more answers
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