How many ounces does a cat drink each day?

Mathematics

2 answers:

Lerok [7]3 years ago

7 0

Answer:

You mean ounces of water yes?

Cats drink between 5 to 10 fluid ounces of water per day

Step-by-step explanation:

jolli1 [7]3 years ago

5 0

Cats need between 3.5-4.5 ounces of water per 5 pounds of body weight per day. So if you have a 10 pound cat, then they should be consuming between 7-9 ounces per day

You might be interested in

A scuba diver is swimming in the ocean 10 feet below sea level. Then, she dives down 12

Elis [28]

Answer:

22 ft

Step-by-step explanation:

Simply add 12 to 10 and you'll get the relative position.

5 0

3 years ago

Read 2 more answers

Jessica is shopping for a new car. She found a blue car that has a 12-gallon gas tank and can go 384 miles on one tank. She foun

adelina 88 [10]

Answer:

Silver car

Step-by-step explanation:

It seems pretty hard but it's actually REALLY easy. gas mileage means the number of miles you can go on a particular amount of gallons. But the gallons have to be the same for both cars so that it's fair.

so let's go with 10 gallons. pretty broad number right?

so to get 12 gallons(the gallons for the blue car) to 10, We divide it by 12 then multiply it by 10. Try it yourself, (12/12)*10=???

then we do that to 384 (the miles for the blue car)

(384/12)*10=320

so 320 is the mileage for the first car. Repeat the steps for the silver car!

(14/14)*10=10

so then: (504/14)*10= 360.

So which is bigger, 320 or 360?

360 is bigger, meaning it has better gas mileage.

5 0

2 years ago

You are curious about the average number of yards Matthew Stafford throws for each game for the Detroit Lions. You randomly sele

Damm [24]

Answer:

The margin of error for this estimate is of 14.79 yards per game.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.093