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2 years ago

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Mathematics

1 answer:

Zepler [3.9K]2 years ago

7 0

Answer:

9/28.26

Step-by-step explanation:

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Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi

ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0

2 years ago

Which expression is equivalent to the expression shown?

choli [55]

<h3>Answer: 5^24</h3>

<h2>Maybe it can be your answer but i am not sure that it is fixed answer </h2>

5 0

3 years ago

Use mental math to solve the problem 8.02 − 5.98

Zinaida [17]

Round off 8.02 to 8 and 5.98 to 6. Then subtract: 8 - 6 = 2 (approximately)

4 1

3 years ago

Read 2 more answers

Consider all numbers consisting of four different digits all between 1 and 9 . How many of these are odd

Slav-nsk [51]

Answer:

1680

Step-by-step explanation:

Considering repeatition is not allowed.

We can use permutation to reach to the required answer.

Consider four digits to be placed in four boxes. Now for the number to be odd, unit digit must be odd. Therefore, unit digit can only be filled by 1, 3, 5,7, or 9. That is 5 ways. Now, other three boxes can be filled with 8, 7 and 6 ways respectively.

Therefore, Total numbers = 5×8×7×6 = 1680

7 0

3 years ago

HELP consider the table of values shown . The relationship of x to y is represented by which equation ?

saw5 [17]

The answer is B.

Whatever the x value is you have to add 9 to it.

7 0

3 years ago