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3 years ago

14

Which situations would be represented with a positive number? Check all that apply.

2 answers:

Ratling [72]3 years ago

8 0

Answer:

A and e

Step-by-step explanation:

Oduvanchick [21]3 years ago

6 0

Answer:

a and e only

Step-by-step explanation:

did the test

hoped this :):):):):):):):):):):):):):):):):)

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Does anyone know the answer and how to solve?

Valentin [98]

First box should be: 2 bc of the second statement
second box (top right): 5 bc 12 students total, subtract from rest (u do this last)
third box: 1 bc all that’s leftover from first box
fourth box (bottom right) 5 bc of third statement
basically, for two way tables each box must apply/be applied to two topics. hope this helps

4 0

3 years ago

Read 2 more answers

1. Use the figure below to answer the questions.<br><br> (a) Solve for x.

Dmitry [639]

Let's see what to do buddy...

_________________________________

The sum of the angles of each n-sided figure is found in the following equation :

$(n - 2) \times 180$

The question's figure is 5-sindes figure

so the sum the angles equal :

$(5 - 2) \times 180 = 3 \times 180 = 540 \\$

So we have :

$90 + 107 + 144 + 138 + x = 54 0 \\$

$479 + x = 540$

Subtract the sides of the equation minus 479

$x = 540 - 479$

$x = 61$

And we're done.

Thanks for watching buddy good luck.

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5 0

3 years ago

The lengths of the legs of a right triangle are 8 inches and 9 inches. What is the length of the hypotenuse? Round to the neares

patriot [66]

Hyp^2 = 8^2 + 9^2
hyp^2 = 64 + 81
hyp^2 = 145
hot = 12 inch

6 0

3 years ago

Which represents the solution(s) of the graphed system of equations, y = x2 – 2x and y = –2x – 1? (1, –1) (0, 0) and (0, –1) (0,

olganol [36]

ANSWER

No solution

EXPLANATION

The first equation is

$y = {x}^{2} - 2x$

and the second equation is

$y = - 2x - 1$

We equate the two equations to obtain;

${x}^{2} - 2x = - 2x - 1$

This implies that

${x}^{2} = - 2x + 2x - 1$

${x}^{2} = - 1$

There is no real number whose square is -1.

Therefore, the equation has no solution.

6 0

3 years ago

Read 2 more answers

Triangle $ABC$ has a right angle at $B$. Legs $\overline{AB}$ and $\overline{CB}$ are extended past point $B$ to points $D$ and

Lisa [10]

Answer:

Given :

ABC is a right triangle in which ∠ABC = 90°,

Also, Legs AB and CB are extended past point B to points D and E,

Such that,

$\angle EAC = \angle ACD = 90^{\circ}$

To prove :

$EB\times BD=AB\times BC$

Proof :

In triangles AEC and EBA,

∠EAC= ∠ABE ( right angles )

∠CEA = ∠AEB ( common angles )

By AA similarity postulate,

$\triangle AEC \sim \triangle EBA$ ,

Similarly,

$\triangle AEC \sim \triangle ABC$

$\implies\triangle EBA\sim \triangle ABC-----(1)$

Now, In triangles ADC and CBD,

∠ACD = ∠CBD ( right angles )

∠ADC= ∠BDC ( common angles )

By AA similarity postulate,

$\triangle ADC \sim \triangle CBD$ ,

Similarly,

$\triangle ADC \sim \triangle ABC$

$\implies \triangle CBD\sim \triangle ABC-----(2)$

From equations (1) and (2),

$\triangle EBA\sim \triangle CBD$

The corresponding sides of similar triangles are in same proportion,

$\frac{EB}{BC}=\frac{AB}{BD}$

$\implies EB\times BD=AB\times BC$

Hence, proved....

5 0

3 years ago