- A 9,300 kg. railroad car traveling at a velocity of 15m/s strikes a second boxcar
1 answer:
Answer:
13950kg
Explanation:
If we make the system both railroad cars, we know that the momentum of the whole system doesn't change because the forces are internal.
Let a be the mass of the second car.
The original momentum is 9300*15 kg*m/s+ a*0 kg*m/s = 139500 kg*m/s
After sticking together, the momentum is (9300+a)kg*6m/s, which should be equal to 139500 kg*m/s
Therefore (9300+a)*6 = 139500
9300+a = 23250
a = 13950 kg
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