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Alinara [238K]
2 years ago
9

An 8 kilogram bowling ball is rolling in a straight line toward you. if its momentum is 16 kg* m/s, how fast is it traveling ?

Physics
1 answer:
morpeh [17]2 years ago
6 0
From the information given, The mass of the bowling ball is 8 Kilograms and the momentum with which it is moving is 16 kg m/s. We use the formula p = m × v Where p is the momentum, m is the mass and v is the velocity. We need velocity so we rewrite the equation thus: P = mv, therefore p/m = v or v = p/m In our case p = 16 and m = 8 v = p/m v = 16/8 v = 2 Therefore the bowling ball is travelling at 2m/s
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Heptane is always composed of 84.0% carbon and 16.0% hydrogen. This illustrates the law of multiple proportions. conservation of
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Answer: Option C

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An object is 15 cm in front of a diverging lens with a
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A) See ray diagram in attachment (-6.0 cm)

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\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

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f = -10 cm is the focal length (negative for a diverging lens)

p = 15 cm is the distance of the object from the lens

Solving for q,

\frac{1}{q}=\frac{1}{-10 cm}-\frac{1}{15 cm}=-0.167 cm^{-1}

q=\frac{1}{-0.167 cm^{-1}}=-6.0 cm

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h_i = - h_o \frac{q}{p}

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Since q < 0 and p > o, we have that h_i >0, which means that the image is upright.

C) The image is virtual

As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.

This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual

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Answer:

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