Answer
given,
mass of the hiker = 66.5 kg
elevation of the hiker,h₁ = 1270 m
elevation of top peak,h₂ = 2660 m
a) Change in potential energy
Δ PE = m g h₂ - m g h₁
Δ PE = m g (h₂ - h₁)
Δ PE = 66.5 x 9.8 x (2660 - 1270)
Δ PE = 905863 J
b) Minimum work require by the hiker will be equal to Δ PE = 905863 J
c) yes, it can be more than this, if friction is present on the surface.
Answer:
The minimum difference between the lengths of the two tubes should be 0.385 meters.
Explanation:
As we known that for any two waves to arrive in phase at any point the difference in the path traveled by the waves should be an integral multiple of the wavelength of the wave.
Mathematically we can write:
For the given wave we have
Applying values we get
Thus the minimum difference in the lengths of the tubes can be obtained by putting the value of n = 1
To solve this problem we should apply Newton's third law for which it is defined that there must be an equal reaction in the opposite direction.
From this law, if Car A generates a force on car B, that car must have opposed a force exactly the same but in the opposite direction. The car A moved to the left and generates a force of 900lb so the magnitude of the force in the car B is also 900lb but to the right (opposite direction to the first car)
The correct option is 900lb to the right.
Answer:
a = 0.009 J
b = 0.19 m/s
c = 0.005 J and 0.004 J
Explanation:
Given that
Mass of the object, m = 0.5 kg
Spring constant of the spring, k = 20 N/m
Amplitude of the motion, A = 3 cm = 0.03 m
Displacement of the system, x = 2 cm = 0.02 m
a
Total energy of the system, E =
E = 1/2 * k * A²
E = 1/2 * 20 * 0.03²
E = 10 * 0.0009
E = 0.009 J
b
E = 1/2 * k * A² = 1/2 * m * v(max)²
1/2 * m * v(max)² = 0.009
1/2 * 0.5 * v(max)² = 0.009
v(max)² = 0.009 * 2/0.5
v(max)² = 0.018 / 0.5
v(max)² = 0.036
v(max) = √0.036
v(max) = 0.19 m/s
c
V = ±√[(k/m) * (A² - x²)]
V = ±√[(20/0.5) * (0.03² - 0.02²)]
V = ±√(40 * 0.0005)
V = ±√0.02
V = ±0.141 m/s
Kinetic Energy, K = 1/2 * m * v²
K = 1/2 * 0.5 * 0.141²
K = 1/4 * 0.02
K = 0.005 J
Potential Energy, P = 1/2 * k * x²
P = 1/2 * 20 * 0.02²
P = 10 * 0.0004
P = 0.004 J
3 times 6= 18. The average speed is 19 mph.
hope this helps!
