In order to solve or know the probability of having 2 girls and 2 boys, assumed that a girl is as likely as a girl at each birth, pascal’s triangle will be likely used. And we will be referring to the line 4 of pascal’s triangle, which was 1 4 6 4 1. Then it will look like this: 1 = 4 girls; 4 = 3 girls & 1 boy; 6 = 2 girls & 2 boys; 4 = 3 boys & 1 girl; 1 = 4 boys. And now for the solution in order to get the probability of having 2 girls and 2 boys is to divided into the sum of 1+4+6+4+1.

7 0

4 years ago

You are playing a board game and your playing piece begins the game at start . You roll a single number cube numbered 1 to 6 to

notka56 [123]

Assuming the dice is fair, you have a probability of $\frac{1}{6}$ to roll any number between 1 and 6, inclusive. In other words, you have

$P(1)=P(2)=P(3)=P(4)=P(5)=P(6)=\dfrac{1}{6}$

3 0

3 years ago

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(ii) Using a calculator, or otherwise, determine the exact value, to one decimal place, of 8792-6886 12 X 9 ​

(ii) Using a calculator, or otherwise, determine the exact value, to one decimal place, of 8792-6886 12 X 9