|Ten Mils| Mils|100 thousands|10 thousands|Thousands|100's|Tens|Units |
|-----------|------|--------------------|------------------|---------------|-------|---------------|
| 6 | 5 | 5 | 0 | 0 | 0 | 0 |
You can find easily the solution
Step-by-step explanation:
I think this might help
9514 1404 393
Answer:
7
Step-by-step explanation:
All of the digits in the given number are significant. There are 7 significant digits.
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<em>Comment on other cases</em>
When there are non-zero digits to the left of the decimal point in a number with a decimal point, all of the digits are significant.
When there are no non-zero digits to the left of the decimal point, leading zeros are not significant. All digits following the leading zeros are significant.
In a number with no decimal point, the leading and trailing zeros are not significant.
If the number is written in scientific notation, all digits of the mantissa are significant. (This can be a way to ensure the correct number of significant digits is known in a number with trailing zeros.)
A simple way to solve for consecutive numbers is to divide the sum number by the number of numbers needed. So 310 ÷ 5, which equals 62. That is the middle consecutive number.
To find the other 4 numbers, since they are all even, sinply add 2 to the middle number to find one, add 2 to that to find another, subtract 2 from the middle number to fine the third, and subtract 2 from that to find the final one.
62 + 2 = 64
64 + 2 = 66
62 - 2 = 60
60 - 2 = 58
so your numbers are 58, 60, 62, 52, and 66. Together they add up to 310.
(I may have done this a non-standard way, bit it was the way that made the most sense in my head.)
