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CaHeK987 [17]
3 years ago
15

What is the exponential regression equation for the data set?

Mathematics
2 answers:
Inessa05 [86]3 years ago
4 0
Y^=323.905•0.875x because it is the correct answer
Vilka [71]3 years ago
3 0

Answer:

y=323.905 \cdot 0.875^x

Step-by-step explanation:

Given :

x                    y

14                   45

16                   45

18                   33

20                   26

20                   16

25                   14

26                   9

Solution:

General form of equation : y=AB^x

Using the exponential regression calculator we get the output

A = 323.905

B = 0.875469

Substituting the values in the general form

y=323.905 \cdot 0.875^x

Hence Option C is correct.

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Please help me with my math problem 25 points for the step-by-step explanation.
Ghella [55]

Step-by-step explanation:

S + L = 6 => L= 6-S

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5 0
3 years ago
Read 2 more answers
On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t
Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

The angle at which hailstones falling relative to the cyclist is \theta = 36.86^\circ

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of 2\hat{i}-6\hat{k}\text{ m/s} . If a cyclist travels through the hail at 10\hat{i} \text{ m/s}.

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is V_h=2\hat{i}-6\hat{k}\text{ m/s}

The velocity of the cyclist travels through the hail is V_c=10\hat{i} \text{ m/s}

The velocity of the hail relative to the cyclist is given by,

V_{hc}=V_h-V_c

Substitute the value in the formula,

V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}

V_{hc}=-8\hat{i}-6\hat{k}

So, The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

Now, The angle of hails falling relative to the cyclist is given by

\theta = \tan^{-1}(\frac{-6}{-8})

\theta = \tan^{-1}(\frac{3}{4})

\theta = 36.86^\circ

So, The angle at which hailstones falling relative to the cyclist is  \theta = 36.86^\circ

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Answer:

90

Step-by-step explanation:

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