5(15)+(15)(15)=75+225
=300
You always start by simplifying.
6b-49=2<span>(</span>b-3) becomes 6b-49=2b-6
From there you can group the b's together by subtracting 2b from both sides, leaving you with 4b-49=-6
Now you can get the b's alone by adding 49 (to cancel out -49) to both sides, giving you 4b=43, You're still trying to get b by itself, so what you'll do is divide both sides by 4, giving you b=10.75
Answer:
(2) Real and equal (i.e., repeated roots), if D = 0.
Step-by-step explanation:
.In a quadratic equation ax2 + bx + c = 0, if discriminant is D= b2 - 4ac, then roots of the quadratic equation are
Real and equal (i.e., repeated roots), if D = 0.
If the D > b² - 4ac then it's real and distinct.
Answer: D) 13y^25 and 2y^25
Like terms involve the same variables, and each of those variables must have the same exponents.
Another example of a pair of like terms would be 5x^3y^2 and 7x^3y^2. Both involve the variable portion "x^3y^2" which we can replace with another variable, say the variable z. That means 5x^3y^2 becomes 5z and 7x^3y^2 becomes 7z. After getting to 5z and 7z, it becomes more clear we have like terms.
That's "5 to the negative seventh power," and is equal to
1 1
---------- = --------- . I would accept "1/(5^7)" as correct.
5^7 78125
