Area of a circle is pi x r ^2
R = diameter/2
R = 1.8/2 = 0.9
Area = 3.142 x 0.9^2
Area = 2.5 square cm.
Yes the triangle is a right triangle so draw the beard that’s on box A
A radius of a circle or sphere is any of the line segments from its center to its perimeter, and in more modern usage, it is also their length. Set up the formula for the area of a circle. The formula is A = π r 2 it equals the area of the circle, and r equals the radius.
Solve for the radius.
Plug the area into the formula.
Divide the area by.
Take the square root.
![\Large\texttt{Answer}](https://tex.z-dn.net/?f=%5CLarge%5Ctexttt%7BAnswer%7D)
![equation=](https://tex.z-dn.net/?f=equation%3D)
![\bold{y=5x-33}](https://tex.z-dn.net/?f=%5Cbold%7By%3D5x-33%7D)
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![\Large\texttt{Process}](https://tex.z-dn.net/?f=%5CLarge%5Ctexttt%7BProcess%7D)
<em>⇨ Use the formula below</em>
<em />![\bf{y-\hfill\stackrel{y \:co-ordinate}{y1}=\hfill\stackrel{slope}{m}(x-\hfill\stackrel{x\:co-ordinate}{x1)}}](https://tex.z-dn.net/?f=%5Cbf%7By-%5Chfill%5Cstackrel%7By%20%5C%3Aco-ordinate%7D%7By1%7D%3D%5Chfill%5Cstackrel%7Bslope%7D%7Bm%7D%28x-%5Chfill%5Cstackrel%7Bx%5C%3Aco-ordinate%7D%7Bx1%29%7D%7D)
<em>⇨ Substitute the parameters:</em>
<em />
<em />![\bold{y-(-8)=5(x-5)}](https://tex.z-dn.net/?f=%5Cbold%7By-%28-8%29%3D5%28x-5%29%7D)
![\bold{y+8=5x-25}](https://tex.z-dn.net/?f=%5Cbold%7By%2B8%3D5x-25%7D)
![\bold{y=5x-33}](https://tex.z-dn.net/?f=%5Cbold%7By%3D5x-33%7D)
Hope that helped
Answer:
1840
Step-by-step explanation: