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vovangra [49]
3 years ago
11

Veata wants to know what percent of students at her school are left-hand dominant. Veata recalls that when students were randoml

y assigned to groups she was the only student in the group of 8 that was left-hand dominant. She also notices that 7 of the 28 students in her art class are left-hand dominant. Which sample should be used to determine the best estimate for the percent of students at the school who are left-hand dominant? Circle one of the following.
randomly assigned group

the entire art class

Explain your reasoning and any concerns about the choices above.
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0
Randomly assigned group. the art class isn't random and only consists of a select type of people--it is not a representative sample; maybe more left handed people enjoy art than do right handed people! therefore, even though the randomly assigned group is smaller, it is the better estimate.
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Step-by-step explanation:

because if you count the number it will be-6

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2 years ago
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Nesterboy [21]

Answer:

\dfrac{1}{2}

Step-by-step explanation:

Given the function h(x)=\dfrac{1}{8}x^3-x^2

The average rate of change of the function h(x) over the interval a\le x\le b can be calculated using formula

\dfrac{h(b)-h(a)}{b-a}

In your case,

a=-2,\\ \\b=2,

so the average rate of change is

\dfrac{h(2)-h(-2)}{2-(-2)}\\ \\=\dfrac{(\frac{1}{8}\cdot 2^3-2^2)-(\frac{1}{8}\cdot (-2)^3-(-2)^2)}{4}\\ \\=\dfrac{(1-4)-(-1-4)}{4}\\ \\=\dfrac{-3+5}{4}\\ \\=\dfrac{2}{4}\\ \\=\dfrac{1}{2}

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3 years ago
Julie bought a drink for $2.99, two bags of chips for $1.29 each, and some gasoline at a convenience store. The price of gasolin
mylen [45]
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Which expression is three less than the product of a number and two,increased by five
Tpy6a [65]

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2 years ago
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Alex17521 [72]

Answer:

6.33... and 0.333...

Step-by-step explanation:

The quadratic formula is


x=\frac{-b+\sqrt{b^2-4ac} }{2a}.


It is important because while some quadratics are factorable and can be solved not all are. The formula will solve all quadratic equations and can also give both real and imaginary solutions.  Using the formula will require less work than finding the factors if factorable. We will substitute a=9, b=-54 and c=-19.

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-54)+/-\sqrt{(-54)^2-4(9)(-19)} }{2(9)}\\x=\frac{54+/-\sqrt{2916+684} }{18}

We will now solve for the plus and the minus.

The plus,,,

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and the minus...

x=\frac{54-\sqrt{3600}}{18}\\x=\frac{54-60}{18}\\x=\frac{-6}{18}\\x=-0.333...

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