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vovangra [49]
2 years ago
11

Veata wants to know what percent of students at her school are left-hand dominant. Veata recalls that when students were randoml

y assigned to groups she was the only student in the group of 8 that was left-hand dominant. She also notices that 7 of the 28 students in her art class are left-hand dominant. Which sample should be used to determine the best estimate for the percent of students at the school who are left-hand dominant? Circle one of the following.
randomly assigned group

the entire art class

Explain your reasoning and any concerns about the choices above.
Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
7 0
Randomly assigned group. the art class isn't random and only consists of a select type of people--it is not a representative sample; maybe more left handed people enjoy art than do right handed people! therefore, even though the randomly assigned group is smaller, it is the better estimate.
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Help me please !!!!!!!!!!!!!!
tensa zangetsu [6.8K]

Answer:

\large\boxed{V=\dfrac{49\pi}{3}\ in^3}\approx51.29\ in^3}

Step-by-step explanation:

The formula of a volume of a cone:

V=\dfrac{1}{3}\pi r^2H

r - radius

H - height

We have

r = (7 : 2) in = 3.5 in

H = 4 in

Substitute:

V=\dfrac{1}{3}\pi(3.5)^2(4)=\dfrac{1}{3}\pi(12.25)(4)=\dfrac{49\pi}{3}\ in^3

\pi\approx3.14\\\\V\approx\dfrac{(49)(3.14)}{3}\approx51.29\ in^3

5 0
3 years ago
Find the solutions to x2 = 20.
Gemiola [76]

Answer:

B.

Step-by-step explanation:

x^2=20; \ => \ \left[\begin{array}{ccc}x=\sqrt{20} \\x=-\sqrt{20} \end{array} \ => \ \left[\begin{array}{ccc}x=2\sqrt{5} \\x=-2 \sqrt{5} \end{array}

3 0
2 years ago
The product of (4z2 + 7z – 8) and (–z + 3) is –4z3 + xz2 + yz – 24.
jeka57 [31]
x is equal to 5 and y is equal to 29


9 0
2 years ago
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Q4.
goblinko [34]

The coding of the statistic is used to make it easier to work with the large sunshine data set

  • The mean of the sunshine is 3.05\overline 6
  • The standard deviation is approximately  <u>18.184</u>

<u />

Reason:

The given parameters are;

The sample size, n = 3.

∑x = 947

Sample corrected sum of squares, Sₓₓ = 33,065.37

The mean and standard deviation = Required

Solution:

Mean, \ \overline x = \dfrac{\sum x_i}{n}

The mean of the daily total sunshine is therefore;

Mean, \ \overline x = \dfrac{947}{30} \approx 31.5 \overline 6

s = \dfrac{x}{10 } - \dfrac{1}{10}

  • E(s) = \dfrac{Ex}{10 } - \dfrac{1}{10}

E(s) = \dfrac{31.5 \overline 6}{10 } - \dfrac{1}{10} = 3.05 \overline 6

  • The mean ≈ 3.05\overline 6

Alternatively

,The \ mean \  of \  the \  daily  \ total  \ sunshine,  \, s = \dfrac{31.5 \overline 6 - 1}{10 } = 3.05\overline 6

The mean of the daily total sunshine, \overline s ≈3.05\overline 6

  • Var(s) = Var \left(\dfrac{x}{10 } - \dfrac{1}{10} \right)

Var(s) = \left(\dfrac{1}{10}\right)^2 \times Var \left(x \right)

Therefore;

Var(s) = \left(\dfrac{1}{10}\right)^2 \times 33,065.37 = 330,6537

Therefore;

  • s = \sqrt{330.6537} \approx 18.184

The standard deviation, s_s ≈ <u>18.184</u>

Learn more about coding of statistic data here:

brainly.com/question/14837870

3 0
2 years ago
a cake recipe calls for 2 cups of flour. you want to make 2/5 of the recipe. how many cups of flour should you use
kvasek [131]
The answer is going to be 1/4 of a cup
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3 years ago
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