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Mnenie [13.5K]
3 years ago
7

Drag the tiles to the correct boxes to complete the pairs.

Mathematics
2 answers:
geniusboy [140]3 years ago
6 0

Answer:

1 - 6/125

2 - 8/125

3- 1/125

4- 36/125

Step-by-step explanation:

1- 6/125

2 - 8/125

3 - 1/125

4 - 36/125

shusha [124]3 years ago
5 0

Answer:

first one - 6/125

second one - 8/125

third one - 1/125

fourth one - 36/125

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Hitman42 [59]

Answer:

20x30xH=7000

11.6666 , depends on how much you need to round it. if 2 sig figs, round it to 12.

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2 years ago
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Suppose there is a pile of​ quarters, dimes, and pennies with a total value of ​$1.06. ​How much of each coin can be present wit
SpyIntel [72]
Hello,

I note (a,b,c) the result of a quarters, b dimes and c pennies:


2 solutions:
106=( 3, 3, 1)=( 1, 8, 1)



106=( 0, 0, 106) but : 100= 0*25+ 0*10+ 100
106=( 0, 1, 96) but : 100= 0*25+ 1*10+ 90
106=( 0, 2, 86) but : 100= 0*25+ 2*10+ 80
106=( 0, 3, 76) but : 100= 0*25+ 3*10+ 70
106=( 0, 4, 66) but : 100= 0*25+ 4*10+ 60
106=( 0, 5, 56) but : 100= 0*25+ 5*10+ 50
106=( 0, 6, 46) but : 100= 0*25+ 6*10+ 40
106=( 0, 7, 36) but : 100= 0*25+ 7*10+ 30
106=( 0, 8, 26) but : 100= 0*25+ 8*10+ 20
106=( 0, 9, 16) but : 100= 0*25+ 9*10+ 10
106=( 0, 10, 6) but : 100= 0*25+ 10*10+ 0
106=( 1, 0, 81) but : 100= 1*25+ 0*10+ 75
106=( 1, 1, 71) but : 100= 1*25+ 1*10+ 65
106=( 1, 2, 61) but : 100= 1*25+ 2*10+ 55
106=( 1, 3, 51) but : 100= 1*25+ 3*10+ 45
106=( 1, 4, 41) but : 100= 1*25+ 4*10+ 35
106=( 1, 5, 31) but : 100= 1*25+ 5*10+ 25
106=( 1, 6, 21) but : 100= 1*25+ 6*10+ 15
106=( 1, 7, 11) but : 100= 1*25+ 7*10+ 5
106=( 1, 8, 1) is good
106=( 2, 0, 56) but : 100= 2*25+ 0*10+ 50
106=( 2, 1, 46) but : 100= 2*25+ 1*10+ 40
106=( 2, 2, 36) but : 100= 2*25+ 2*10+ 30
106=( 2, 3, 26) but : 100= 2*25+ 3*10+ 20
106=( 2, 4, 16) but : 100= 2*25+ 4*10+ 10
106=( 2, 5, 6) but : 100= 2*25+ 5*10+ 0
106=( 3, 0, 31) but : 100= 3*25+ 0*10+ 25
106=( 3, 1, 21) but : 100= 3*25+ 1*10+ 15
106=( 3, 2, 11) but : 100= 3*25+ 2*10+ 5
106=( 3, 3, 1) is good
106=( 4, 0, 6) but : 100= 4*25+ 0*10+ 0






5 0
3 years ago
You want to place a towel bar that is 10 1⁄4 inches long in the center of a door that is 26 1⁄3 inches wide. How far should you
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\frac{26 \frac{1}{3} -10 \frac{1}{4}}{2}=\\ \frac{ \frac{79}{3} - \frac{41}{4} }{2} =\\ \frac{ \frac{79}{3} * \frac{4}{4} - \frac{41}{4} * \frac{3}{3} }{2} =\\ \frac{ \frac{356}{12}- \frac{123}{12}  }{2} =\\ \frac{ \frac{233}{12} }{2} =\\ \frac{233}{24} =\\ 9\frac{17}{24}

9 17/24 inches.
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There would be 2 groups. The greatest amount in each pile is 2 cards.
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