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Alexxx [7]
3 years ago
12

Maths assignment y^2-36

Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

Since both terms are perfect squares, factor using the difference of squares formula,  

a ^2 − b ^2 = ( a + b ) ( a − b )

where  

a = y

and  

b = 6  

( y + 6 ) ( y − 6 )

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If the limit of f(x) as x approaches 8 is 3, can you conclude anything about f(8)?
natali 33 [55]

If the limit of f(x) as x approaches 8 is 3, can you conclude anything about f(8)? The answer is No. We cannot. See the explanation below.

<h3>What is the justification for the above position?</h3>

Again, 'No,' is the response to this question. The justification for this is that the value of a function does not depend on the function's limit at a given moment.

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The limit of a function at a position where there is a hole in the function will exist, but the value of the function will not.

<h3>What is limit in Math?</h3>

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6 0
1 year ago
u don’t need to do the explanations for the questions. Just answer each expression with correct/incorrect. thank-you :)
tigry1 [53]

Answer:

correct

incorrect

incorrect

correct

5 0
3 years ago
How to find the vertex of a parabola given a quadratic equation?
Nat2105 [25]
let \: f(x) = ax {}^{2} + bx + c \\ thus \: f(x) \: represents \: a \: parabola \: whose \: axis \: is \: parallel \: to \: the \: y \: axis \: and \: vertex \: is \: \frac{ - b}{2a} ,\frac{ - d}{4a} \\

At the respective max and min values

8 0
3 years ago
Merta reports that 74% of its trains are on time. A check of 60 randomly selected trains shows that 38 of them arrived on time.
kenny6666 [7]

Answer:

No, the on-time rate of 74% is not correct.

Solution:

As per the question:

Sample size, n = 60

The proportion of the population, P' = 74% = 0.74

q' = 1 - 0.74 = 0.26

We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.

Now,

The proportion of the given sample, p = \frac{38}{60} = 0.634

Therefore, the probability is given by:

P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]

P(p\leq 0.634) = P[z\leq -1.87188]

P(p\leq 0.634) = P[z\leq -1.87] = 0.0298

Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %

Thus the on-time rate of 74% is incorrect.

6 0
2 years ago
What is 9/2÷3/4?
Drupady [299]

Answer:

6

Step-by-step explanation:

I used a calculator. :)

3 0
2 years ago
Read 2 more answers
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