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PilotLPTM [1.2K]
1 year ago
5

Malik walks 5 blocks per minute. How many blocks will he walk in 6 minutes? 5 blocks

Mathematics
1 answer:
Travka [436]1 year ago
5 0
30 blocks because 6 * 5 = 30
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Help plz someone help me plz ty
MrRa [10]

Answer: 18.75 for each girl

Step-by-step explanation:

First you take the unit rate 2.50 multiply by 5.

2.50 x 5 = 12.50

12.50 x 3 = 37.50

37.50 / 2 = 18.75

7 0
3 years ago
find the coordinate of U' after a 90° counterclockwise rotation of the triangle about the origin and then a translation of 2 uni
SVETLANKA909090 [29]

Answer: U' = (0, 1)

<u>Step-by-step explanation:</u>

U = (3, -5)

rotate 90° counterclockwise means (x, y) = (-y, x)

new U = (5, 3)

down 2 units means subtract 2 from the y-coordinate

newer U = (5, 1)

left 5 units means subtract 5 from the x-coordinate

U' = (0, 1)

6 0
3 years ago
Janice swam in the 400​ ___ backstroke.
ruslelena [56]
Meter/ yard. Likely meter since that is high/college standard
7 0
3 years ago
Write an equation of a parabola that passes through (3,-30) and has x-intercepts of -2 and 18. Then find the average rate of cha
Nookie1986 [14]

Answer:

The equation of the parabola is y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}.  The average rate of change of the parabola is -4.

Step-by-step explanation:

We must remember that a parabola is represented by a quadratic function, which can be formed by knowing three different points. A quadratic function is standard form is represented by:

y = a\cdot x^{2}+b\cdot x + c

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

a, b, c - Coefficients, dimensionless.

If we know that (3, -30), (-2, 0) and (18, 0) are part of the parabola, the following linear system of equations is formed:

9\cdot a +3\cdot b + c = -30

4\cdot a -2\cdot b +c = 0

324\cdot a +18\cdot b + c = 0

This system can be solved both by algebraic means (substitution, elimination, equalization, determinant) and by numerical methods. The solution of the linear system is:

a = \frac{2}{5}, b = -\frac{32}{5}, c = -\frac{72}{5}.

The equation of the parabola is y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}.

Now, we calculate the average rate of change (r), dimensionless, between x = -2 and x = 8 by using the formula of secant line slope:

r = \frac{y(8)-y(-2)}{8-(-2)}

r = \frac{y(8)-y(-2)}{10}

x = -2

y = \frac{2}{5}\cdot (-2)^{2}-\frac{32}{5}\cdot (-2)-\frac{72}{5}

y(-2) = 0

x = 8

y = \frac{2}{5}\cdot (8)^{2}-\frac{32}{5}\cdot (8)-\frac{72}{5}

y(8) = -40

r = \frac{-40-0}{10}

r = -4

The average rate of change of the parabola is -4.

3 0
3 years ago
Need help asap !
frutty [35]
The triangle to solve for has a leg or 12 feet, hypotenuse of 20 feet, so solve for Pythagoras a^{2}  +  b^{2}  =  c^{2}  for a

a =  \sqrt{c^{2} -b^{2}}

a = 16 feet
5 0
3 years ago
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