Answer:
Step-by-step explanation:
To find the center and the radius, we need to put the equation in the (x-a)^2+(y-b)^2=r^2 [a is the x-coordinate, b is the y-coordinate, and r is the radius].
(x+6)^2+(y+7)^2 - 36 - 49 + 69 = 0
(x+6)^2+(y+7)^2 - 16 = 0
(x+6)^2+(y+7)^2 = 16
(x+6)^2+(y+7)^2 = 4^2
The center is (-6,-7) and the radius is 4.
Hope this helps!
Given:
There are given the edge of the cube-shaped aquarium has 3 feet.
Explanation:
To find the value, we need to use the volume of the cube formula:
So,
From the formula of volume:

Where
a represents the value of edge.
So,
Put the value of edge into the above formula:
Then,

Now,
The water has a density of 62 pounds per cube foot.
According to the question:
If the weight of 1 cubic foot of water is 62 pounds, then the weight of 27 cube feet water is:

Final answer:
Hence, the water weight of the full aquarium is 1674 pounds, and the table only susupports00 pounds. So the table cannot hold the aquarium.
And,
No, the density of water would not change.
The answer would be 1440 feet^2, becasue for area you have to multiply the width, length, and depth. You bascally would draw a 3D rectangle and label the depth, height, and width. That would be your diagram.
Since line AB is multiplied by 3 to get line XY, you would multiply 2 by 3 to get 6. The answer is J, or 6. Hope this helps!