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Dmitriy789 [7]
3 years ago
14

0.07 is what of 0.7

Mathematics
1 answer:
MakcuM [25]3 years ago
7 0

The answer to this is 0.049

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Elanso [62]
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5 0
3 years ago
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5. -4n + 7 + 2n =1
Minchanka [31]
5.
-4n+ 7+ 2n= 1
⇒ (-4n+ 2n)+ 7= 1 (combine like terms)
⇒ -2n= 1-7
⇒ -2n= -6
⇒ n= -6/(-2)
⇒ n= 3

Final answer: B. 3~

6. 4(y-4)= 8
⇒ y-4= 8/4
⇒ y-4= 2
⇒ y= 2+4
⇒ y= 6

Final answer: D. 6~


3 0
3 years ago
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⅔ x 6/7 ÷ 8/14 help please​
ahrayia [7]

Answer:

1

Step-by-step explanation:

\frac{2}{3} *\frac{6}{7} ÷ \frac{8}{14}

= \frac{2}{3} *\frac{6}{7} *\frac{14}{8}

=\frac{2}{3} *\frac{6}{7} *\frac{7}{4}

=\frac{2*6*7}{3*7*4}

=\frac{84}{84}

=1

8 0
3 years ago
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Given a battery rated at 350 ampere-hours how many hours will the battery be able to provide 7 amperes
coldgirl [10]

From the division computed, it should be noted that the number of hours that the battery will be able to provide 7 amperes will be 50 hours.

The information given is about the division of numbers. It was stated that the battery is rated at 350 ampere-hours.

The number of hours that it will be able to provide 7 amperes will be:

= 350 / 7

= 50 hours.

Learn more about division on:

brainly.com/question/24834472

7 0
2 years ago
can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylind
shutvik [7]

the new radius be to meet the client's need is 4.9 cm .

<u>Step-by-step explanation:</u>

Here we have , can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylindrical can that has the same volume but is 15 cm tall. We need to find What must the new radius be to meet the client's need . Let's find out:

Let we have two cylinders of volume V_1 , V_2 with parameters as follows :

r_1=6cm\\h_1=10cm\\r_2=?\\h_2=15cm

We know that volume of cylinder is \pi r^2h , According to question volume of both cylinder is equal i.e

⇒ V_1=V_2

⇒ \pi (r_1)^2h_1= \pi (r_2)^2h_2

⇒ (r_1)^2h_1= (r_2)^2h_2

⇒ \frac{(r_1)^2h_1}{h_2}= (r_2)^2

⇒ (r_2) =\sqrt{ \frac{(r_1)^2h_1}{h_2}}                   Putting all values

⇒ (r_2) =\sqrt{ \frac{(6)^2(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{36(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{360}{15}}

⇒ (r_2) =\sqrt{24}

⇒ (r_2) =4.9cm

Therefore , the new radius be to meet the client's need is 4.9 cm .

7 0
3 years ago
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