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OLEGan [10]
2 years ago
7

Question 2 (1 point)

Mathematics
2 answers:
bekas [8.4K]2 years ago
8 0

Answer:

A. 48

Step-by-step explanation:

MariettaO [177]2 years ago
4 0

Answer: 48

Step-by-step explanation:

<u><em>I guessed and got it right, trust</em></u>

<u><em></em></u>

<u><em></em></u>

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Firstly, let's factorise each equation individually - to do this, find 2 numbers that when summed add to the value of the second term, and when multiplied give the value of the third term.

7 and 12 give us 4 and 3 (4+3=7, 4*3=12) -- 8 and 15 give us 5 and 3 (5+3=8, 5*3=15)

Now we can rewrite these equations as (y+4)(y+3) and (y+5)(y+3) respectively.

Putting this in a fraction: (y+4)(y+3)/(y+5)(y+3) -- We can clearly see that there is a y+3 on both sides of the fraction, and given there are no terms outside of the brackets being multiplied, we can directly cancel.

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garik1379 [7]

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