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Sergeeva-Olga [200]
3 years ago
12

Help please ASAP!!!! I NEED CORRECT ANSWERS ONLY FOR BRAINLIEST

Mathematics
1 answer:
nalin [4]3 years ago
5 0

we are given

tan^2(\theta)(1-cot^2(\theta))

Firstly , we can distribute tan^2 inside

we get

=tan^2(\theta)*1-tan^2(\theta)*cot^2(\theta)

now, we can simplify it

=tan^2(\theta)-tan^2(\theta)*cot^2(\theta)

we know that

tan=1/cot

so, tan^2 will get cancelled with cot^2

=tan^2(\theta)-1

so, option-C..............Answer

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IrinaK [193]
The transformation from 1 to 2 is a translation, as the shape is moved from one point to another with no rotation, reflection, or change in size.

The transformation from 2 to 3 is a reflection, as the shape is now upside down. It is still the same distance from the y-axis.

The answer is D. translation, then reflection.
3 0
2 years ago
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when derek planted a tree it was 36 inches tall. the tree grew 1 1/4 inches per year the tree is now 44 3/4 inches tall. how man
mafiozo [28]
Derek would have planted the tree 7 years ago. You subtract 36 from 44.75 and get 8.75. This is how much the tree grew since he planted it. Then, you'll divide 8.75 by 1.25 (1 1/4) which tells you how many years it has been since he planted the tree. The final answer is 7 years. Hope this helps!
8 0
3 years ago
You know that in a specific population of rainbow trout 15% of the individuals carry intestinal parasites. Assume you obtain a r
kicyunya [14]

Answer:

a) 0.2316 = 23.16% probability that 0 carry intestinal parasites.

b) 0.4005 = 40.05% probability that at least two individuals carry intestinal parasites.

Step-by-step explanation:

For each trout, there are only two possible outcomes. Either they carry intestinal parasites, or they do not. Trouts are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

You know that in a specific population of rainbow trout 15% of the individuals carry intestinal parasites.

This means that p = 0.15

Assume you obtain a random sample of 9 individuals from this population:

This means that n = 9

a. Calculate the probability that __ (last digit of your ID number) carry intestinal parasites.

Last digit is 0, so:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.15)^{0}.(0.85)^{9} = 0.2316

0.2316 = 23.16% probability that 0 carry intestinal parasites.

b. Calculate the probability that at least two individuals carry intestinal parasites.

This is

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.15)^{0}.(0.85)^{9} = 0.2316

P(X = 1) = C_{9,1}.(0.15)^{1}.(0.85)^{8} = 0.3679

P(X < 2) = P(X = 0) + P(X = 1) = 0.2316 + 0.3679 = 0.5995

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5995 = 0.4005

0.4005 = 40.05% probability that at least two individuals carry intestinal parasites.

5 0
2 years ago
Use the method of completing the square to transform the quadratic equation into the equation form (x + p)2 = q.
Brilliant_brown [7]

\text{Use:}(*)\ (a+b)^2=a^2+2ab+b^2\\\\2x^2+2x+1=0\ \ \ \ |:2\\\\x^2+x+0.5=0\\\\x^2+2\cdot x\cdot0.5+0.5=0\\\\\underbrace{x^2+2\cdot x\cdot0.5+0.5^2}_{(*)}-0.5^2+0.5=0\\\\(x+0.5)^2-0.25+0.5=0\\\\(x+0.5)^2+0.25=0\ \ \ \ |-0.25\\\\(x+0.5)^2=-0.25\to D)

Answer: D) (x + 0.5)2 = -0.25

5 0
3 years ago
Someone help me <br> Which expression is equivalent to the given expression? (3m^2n)^3/mn^4
VashaNatasha [74]

The expression (3m²n)³/mn⁴ is equivalent to the expression 9m³n⁻¹.

<h3>What is an equivalent expression?</h3>

The equivalent is the expressions that are in different forms but are equal to the same value.

The expression is given below.

(3m²n)³/mn⁴

By simplifying, we have

9m⁴n³ / mn⁴

9m³n⁻¹

More about the equivalent link is given below.

brainly.com/question/889935

#SPJ1

7 0
2 years ago
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