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Sergeeva-Olga [200]
3 years ago
12

Help please ASAP!!!! I NEED CORRECT ANSWERS ONLY FOR BRAINLIEST

Mathematics
1 answer:
nalin [4]3 years ago
5 0

we are given

tan^2(\theta)(1-cot^2(\theta))

Firstly , we can distribute tan^2 inside

we get

=tan^2(\theta)*1-tan^2(\theta)*cot^2(\theta)

now, we can simplify it

=tan^2(\theta)-tan^2(\theta)*cot^2(\theta)

we know that

tan=1/cot

so, tan^2 will get cancelled with cot^2

=tan^2(\theta)-1

so, option-C..............Answer

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0.441 to its standard form
vlada-n [284]

Answer:

erm

Step-by-step explanation:

4.41 times 10^-1

8 0
3 years ago
Which planet is about 1 /10 of the distance Uranus is from the sun?
tino4ka555 [31]
There is no real planet that is 1/10 the distance Uranus is from the sun, however the planetoid (smaller planet), Vesta is 1/9 the distance Uranus is from the sun.
3 0
3 years ago
Read 2 more answers
The sum of three numbers is 24. the largest number is three times the smallest, and the middle number is four less than the larg
tensa zangetsu [6.8K]
Small number =X
mid number = 3X-4
large number = 3x

X+3X-4+3X=24
7X-4=24
7X-4+4=24+4
7X=28
X=28/7
X=4

S=4
M=3(4) -4=12-4=8
L=3(4)=12

The numbers are 4,8 and 12
6 0
3 years ago
Consider 4 flips of an unfair coin where probability of heads is 0.40. Consider all tosses independent of each other. (a) Compar
romanna [79]

Answer:

a) 0.0256 = 2.56% probability of 4 heads.

0.1296 = 12.96% probability of 4 tails.

b) The probability is 0.0576 = 5.76%.

c) 6 outcomes given 2 heads in 4 tosses. 0.3456 = 34.56% probability of 2 heads in 4 tosses

Step-by-step explanation:

For each throw, we have these following probabilities:

0.4 = 40% probability of heads.

0.6 = 60% probability of tails.

(a) Compare the probability of 4 heads in 4 tosses and 4 tails in 4 tosses.

4 heads:

4 throws, each with 0.4 probability of heads. So

(0.4)^4 = 0.0256

0.0256 = 2.56% probability of 4 heads.

4 tails:

4 throws, each with 0.6 probability of tails. So

(0.6)^4 = 0.1296

0.1296 = 12.96% probability of 4 tails.

(b) Determine the probability of H T H T in 4 tosses.

H = 0.4, T = 0.6. So

p = 0.4*0.6*0.4*0.6 = 0.0576

The probability is 0.0576 = 5.76%.

(c) Determine the number of outcomes that give us 2 heads in 4 tosses in any order. What is the probability of 2 heads in 4 tosses (use (b) and the number of outcomes)

Number of outcomes:

The possible outcomes are:

H - H - T - T

H - T - H - T

H - T - T - H

T - H - H - T

T - H - T - H

T - T - H - H

6 outcomes given 2 heads in 4 tosses.

Each with probability 0.0576, as found in b)

6*0.0576 = 0.3456

0.3456 = 34.56% probability of 2 heads in 4 tosses

8 0
3 years ago
PLEASE help me!!!!!!!! Answer all questions and you will get brainliest!!!!!!!!
den301095 [7]

Answer:

a. 6  

b. 4/3

c. 28

Step-by-step explanation:

For a, you multiply 9 by 2/3

For b, you would do 12 divided by 9

For c, you would do 7 divided by 1/4, or 0.25

Hope this helps.

4 0
4 years ago
Read 2 more answers
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