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erma4kov [3.2K]
3 years ago
8

Find the Measure of one interior angle for each polygon

Mathematics
1 answer:
Illusion [34]3 years ago
3 0

Answer:

5 corners : 108 degrees

6 corners : 120 degrees

Step-by-step explanation:

there are (at least) 2 different views to get the result :

officially (usually the teachers' preferred method) you consider a polygon as a combination of non-overlapping triangles. a polygon with n corners or edges we can split into n-2 such triangles.

each triangle has an angle sum of 180 degree.

so, the polygon angle sum is (n-2)×180 degrees.

and each (internal) angle is then (n-2)×180/n

n = 5 : (5-2)×180/5 = 3×36 = 108 degrees

n = 6 : (6-2)×180/6 = 4×30 = 120 degrees

the second approach (I prefer) goes after the external angles of the polygon.

the sum of all external angles in any polygon is 360 degrees (a full circle).

for n corners/edges each external angle is 360/n.

and the internal angle is then the complement to 180 degrees = 180 - 360/n

n = 5 : 180 - 360/5 = 180 - 72 = 108 degrees

n = 6 : 180 - 360/6 = 180 - 60 = 120 degrees

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The area of circle Z is 64. What is the value of r? r = ____ft
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A nursery has two hundred 7-gallon palm trees to sell, consisting of coconut palm trees, saw palmetto palm trees and christmas p
motikmotik

Total number of trees available to be sold = 200

Selling price of coconut palm trees sell (Pco)= $75 each

Selling price of saw palmetto palm trees sell (Pp) = $45 each

Selling price of christmas palm trees (Pch) = $30 each

Number of saw palmetto palm trees (Np) = 3 × Number of christmas palm trees (Nch)

Let number of coconut palm trees be Nco

Total price paid by developer for all the palm trees = 12,300

So Total number of trees = Nco + Np + Nch

⇒ 200 = Nco + 3×Nch + Nch

⇒ 200 = Nco + 4Nch ................ (i)

Total selling price of trees = Sco × Nco + Sp × Np + Sch × Nch

⇒ 12,300 = 75×Nco + 45×Np + 30×Nch

Dividing above equation by 5

⇒ 2,460 = 15Nco + 9Np + 6Nch

Substituting Np = 3Nch in the above equation

⇒ 2,460 = 15Nco + 9 (3Nch) + 6Nch

⇒ 2,460 = 15Nco + 33Nch ................ (ii)

Mutiply (i) with 15 and subtract from (ii)

⇒ 2,460 - 3,000 = 15Nco + 33Nch - 15Nco - 60Nch

⇒ -540 = 33Nch - 60Nch

⇒ -540 = 27Nch

⇒ Nch=20

If Nch = 20, Np = 3×20 = 60

Since Nco + Np + Nch = 200

⇒ Nco = 200 - (80)

⇒ Nco = 120

Hence, the developer purchased 120 coconut palm trees, 20 christmas palm trees and 60 saw palmetto palm trees.

6 0
3 years ago
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