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Andrews [41]
3 years ago
13

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

ct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Complete the following proof.

Given: AB is diameter of circle O.
AC and BD are tangents

Prove: AC parallel to BD.

Mathematics
1 answer:
Veronika [31]3 years ago
8 0

Answer:

The statements are in regular print, the reasons are bolded

Step-by-step explanation:

1st:AB is the diameter of circle o. Both 1 and 2 are Given

2nd: AC and BD are tangents.

3rd:Ab is perpendicular to AC , AB is perpendicular to BD. Radius is perpendicular to tangent

4th: AC is parallel to BD Lines parallel to same line are congruent.

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How does 4/3y = 36??????????
omeli [17]

Answer:

i think 27

Step-by-step explanation:

27 X 4/3y=36y

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3 years ago
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Rewrite the following equation in slope-inte
Nonamiya [84]

Answer:

y = 13x + 86

Step-by-step explanation:

y−8 =13(x+6); distribute the 13

y - 8 = 13x + 78; now add 8 to both sides

y = 13x + 86; this is the slope intercept form

7 0
3 years ago
Define a cubic polynomial and a binomial use only one variable in each). Show how to use the Vertical Method to multiply these t
Sedbober [7]

Cubic polynomial

{x}^{3}  +  {2x}^{2}  - 5x - 10

Binomial

2x - 3

By vertical method of multiplication we get,

{2x}^{4}  +  {x}^{3}  -  {16x}^{2}  - 5x + 30

8 0
3 years ago
Janeel has a 10-inch by 12-inch photograph. She wants to scan the photograph, then reduce the result
Vaselesa [24]

<u>Complete Question:</u>

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

<u>Correct Answer:</u>

A) (10-x)(12-x)=15

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

<u>Step-by-step explanation:</u>

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

length=10-x\\breadth=12-x

According to question , Area of new image is :

⇒ Area = \frac{1}{8}Length(breadth)

⇒ Area = \frac{1}{8}(10)(12)

⇒ Area = 15

So the equation will be :

⇒ (10-x)(12-x)=15

b. Find the dimensions of the reduced image

Let's solve :  (10-x)(12-x)=15

⇒ 120-10x-12x+x^2=15

⇒ 120-22x+x^2=15

⇒ x^2-22x+105=0

By Quadratic formula :

⇒ x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x = \frac{22 \pm8 }{2}

⇒ x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}

⇒ x = 15 , x =7

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ x =7

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

5 0
3 years ago
I need help... ASAP please
qwelly [4]

Answer:

B

Step-by-step explanation:

because it explains what the graph shows

7 0
3 years ago
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