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ira [324]
3 years ago
13

HURRY PLEASE!!I WILL GIVE BRAINLIEST

Mathematics
1 answer:
Irina18 [472]3 years ago
8 0

Answer:

Step 1 = 9\sqrt{3}

Step 2 = 4

Step 3 = 25

Step-by-step explanation:

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What fomula can be used to describe the sequence? -2/3,-4,-24,-144
Lunna [17]

This is a geometric sequence with n th term formula

a_{n} = a_{1}(r)^{n-1}

where r is the common ratio and a_{1} the first term

here a_{1} = - \frac{2}{3} and

r = \frac{-144}{-24} = \frac{-24}{-4} = 6

a_{n} = - \frac{2}{3}(6)^{n-1}

or in terms of x

f(x) = - \frac{2}{3}(6)^{x-1}



5 0
3 years ago
23) A movie theatre has 900 seats of which 15% are in the balcony. How many seats are NOT in the balcony?
just olya [345]

Answer:

A.765 seats are not in the balcony

Step-by-step explanation:

if 15% are in the balcony then 85% are not in the balcony so..

900 * 0.85 = 765

4 0
2 years ago
Read 2 more answers
Simplify -5-√-44<br><br> i have no idea
Tatiana [17]

Answer:

Undefined

Step-by-step explanation:

The square root of a negative number does not exist in the set of real numbers so it would be Undefined

6 0
3 years ago
A marble factory ships marbles using bags of 10, cases of 100, cartons of 1,000, and boxes of 10,000. The factory has an order f
disa [49]
They factory could use 35 cases of 100 and 7 bags of 10.

I hope my answer helps. =)
6 0
3 years ago
Solve in attachment....​
olga2289 [7]

Answer:

A)2

Step-by-step explanation:

we would like to integrate the following definite Integral:

\displaystyle  \int_{0} ^{1} 5x \sqrt{x} dx

use constant integration rule which yields:

\displaystyle  5\int_{0} ^{1} x \sqrt{x} dx

notice that we can rewrite √x using Law of exponent therefore we obtain:

\displaystyle  5\int_{0} ^{1} x \cdot  {x}^{1/2} dx

once again use law of exponent which yields:

\displaystyle  5\int_{0} ^{1}  {x}^{ \frac{3}{2} } dx

use exponent integration rule which yields;

\displaystyle  5 \left( \frac{{x}^{ \frac{3}{2}  + 1  } }{ \frac{3}{2}  + 1} \right)  \bigg|  _{0} ^{1}

simplify which yields:

\displaystyle  2 {x}^{2}  \sqrt{x}   \bigg|  _{0} ^{1}

recall fundamental theorem:

\displaystyle  2 (  {1}^{2}) (\sqrt{1}  ) - 2( {0}^{2} )( \sqrt{0)}

simplify:

\displaystyle  2

hence

our answer is A

8 0
3 years ago
Read 2 more answers
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