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ira [324]
3 years ago
13

HURRY PLEASE!!I WILL GIVE BRAINLIEST

Mathematics
1 answer:
Irina18 [472]3 years ago
8 0

Answer:

Step 1 = 9\sqrt{3}

Step 2 = 4

Step 3 = 25

Step-by-step explanation:

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Answer:

56

Step-by-step explanation:

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3 years ago
Solve by factoring<br> please help this is timed :(
sdas [7]
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4 0
3 years ago
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Surely help I’ll brainlist.<br><br> construct a histogram to represent these results.
AnnZ [28]

Answer:

Step-by-step explanation:

You need to first put the numbers in suitable catagories

0-120

120-130

130-140

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7 0
2 years ago
WILL GIVE BRAINLIEST
stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph.  A cargo plane left sometime later flying in the same direction at an average speed of 207 mph.  After flying for 5.3 hours the cargo plane caught up with the Air Force plane.  

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, \text { distance travelled }=\text { speed } \times \text { time }

For air force plane \rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }

\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, 159 \times \text { time taken by air force plane }=207 \times 5.3

\Rightarrow =\frac{207 \times 5.3}{159}

\Rightarrow =\frac{1097.1}{159}

Time taken by air force plane = 6.9  hrs

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3 years ago
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jeka57 [31]

Y=3/4x-2 would be your equation :)

You find this with y=mx+b with m being your slope and b being the y-axis point

4 0
3 years ago
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