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Orlov [11]
3 years ago
10

Heather is putting together a square bulletin board for her new room, and the area of the bulletin board is 196 cm^2.

Mathematics
2 answers:
jonny [76]3 years ago
6 0
I think that the answer a would be timesing them and b would be counting all around the numbers
MrRissso [65]3 years ago
5 0
The side length is 14cm. 14x14 = 196
total distance would be 14x4 or 14+14+14+14=56cm
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b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
3 years ago
PLEASSEEEE HELP ASAP , WHAT IS THE SHAPE OF THE BASE AND SURFACE AREA?
zmey [24]

Answer:

Total surface area : 733

The shape of the base is a rectangle with sides 11 in. and 12 in.

Step-by-step explanation:

The shape of the base is a rectangle with sides 11 in. and 12 in.

The surface area is the sum of the areas of the 5 sides.

Area of the base = 11*12 = 132

Area of the two triangles =  (11*16)/2 = 88

Area of the back rectangle = 192

The theorem of Pitagora to find the oblique side: square root of (11*11 + 16*16)= 19.42 in.

So the area of the oblique face: 19.42* 12 = 233 (almost :) )

So total surface area: 132 + 88*2+192+233= 733 square in

3 0
2 years ago
Huilan is 15 years younger than Thomas. The sum of their ages is 33 . What is Thomas's age?
Sphinxa [80]

h = t - 15

h + t = 33

Because we have a value of h, we can plug it into the second equation to solve for t.

t - 15 + t = 33

Add 15 to both sides.

t + t = 48

Combine like terms.

2t = 48

Divide both sides by 2.

t = 24

<h3>Thomas's age is 24.</h3>
6 0
3 years ago
Each equation given below describes a parabola. Which statement best compares their graphs?
kkurt [141]

The answer to this question is

Both Parabolas open to the right, and x= 3y2 is wider than x= 5y2.

(APEX)

8 0
3 years ago
Read 2 more answers
Find the midpoint of AC if A is located at (-4,9) and C is located at (1,31)
aliina [53]
The midpoint of AC is (-1.5, 20)
3 0
3 years ago
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