Hi,
To solve this problem, Let us take the LCM of 10 and 16 which will come 80.
Now suppose the cost price of 10 tables =₹n CP of 80 tables will be ₹ 8n
According to the question, CP of 10 tables is equal to the SP of 16 tables, then
the SP of 16 tables will also be ₹ n.
So, SP of 80 tables will be ₹ 5n
So, Loss = CP-SP
→ 8n - 5n = ₹ 3n
Loss%= (3n×100)/8n
Loss%= 37.5%.
Hence the correct answer will be a <u>loss of 37.5%.</u>
Answer
3
Step-by-step explanation:
(4-1)^2+(8-8)^2=9
square root of 9 is 3
Log16 4 = 2
log base 16 then the number four then set that equal to 2
Converse Perpendicular Transversal Theorem.
If two lines are perpendicular to the same line, then the lines are parallel.
