Answer:
Option A) Circle.
Step-by-step explanation:
We are given the equation:

A general equation of the circle is of the form:

where (h,k) is the center of the circle and r is the radius of circle.
Comparing the two equations, we get,

Thus, the given equation is equation of a circle centered at (3,12) and of radius 5 units.
You walked 5/6 mile
1/3(x2)=2/6
1/2(x3)=3/6
5/6 mile
(You copied 'upper left' twice, and you left out 'lower right'.
But we know what you mean.)
If those are the corners of the wall, then they're ALL in the plane of
the wall (coplanar with it).
It doesn't. One third multiplied by three fourths is one fourth or .25



p, li { white-space: pre-wrap; }
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now on 2)
if the denominator has a higher degree than the numerator, the horizontal asymptote is y = 0, or the x-axis,
in this case, the numerator has a degree of 0, the denominator has 4, thus y = 0
vertical asymptotes occur when the denominator is 0, that is, when the fraction becomes undefined, and for this one, that occurs at
or the y-axis
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now on 3)

now, let's see some transformations templates


now, let's take a peek at g(x)
