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Komok [63]
3 years ago
15

Find the solution for 3x + 7 ≥ -29.

Mathematics
2 answers:
netineya [11]3 years ago
7 0
This the answer yessir

RSB [31]3 years ago
6 0

Answer:

x>=-12

Step-by-step explanation:

3x+7>=-29

3x>=-29-7

3x>=-36

x>=-36/3

x>=-12

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The points represented by the table like on a line. Find the slope of the line.
olchik [2.2K]

Answer:

undefined slope

Step-by-step explanation:

There us change in rise but no change in run or x value. This means is a vertical line and it's slope is undefined.

5 0
3 years ago
A principal of $835 is invested in an account at 4% per quarter simple interest which of the following sequences describes the d
netineya [11]
To solve the question we use the compound interest formula which is given by:
A=p(1+r)^(nt)
where:
A=future value
p=principle
r=rate
n=number of terms
t=time
thus plugging in the values in the formula we shall have:
A=835(1+0.04)^(4t)
simplifying this we get the sequence:
A=835(1.040)^(4t)
Thus the answer to the sequence will be:
A=835(1.040)^(4t)

7 0
3 years ago
Draw at least six different sized rectangles that have an area of 64 square units
olga_2 [115]

Let

x------> the length of the rectangle

y------> the width of the rectangle

we know that

The area of a rectangle is equal to

A=x*y

A=64\ units^{2}

so

x*y=64 --------> equation 1

let's assume different values of x to get the different values of y

<u>case 1)</u> For x=64 units

substitute in the equation 1

x*y=64

y=64/x

y=64/64

y=1\ units      

the dimensions of the rectangle are 64 units x 1 unit

see the draw in the attached figure N 1

<u>case 2)</u> For x=32 units

substitute in the equation 1

x*y=64

y=64/x

y=64/32

y=2\ units

the dimensions of the rectangle are 32 units x 2 units

see the draw in the attached figure N 2

<u>case 3)</u> For x=16 units  

substitute in the equation 1

x*y=64

y=64/x

y=64/16

y=4\ units

the dimensions of the rectangle are 16 units x 4 units

see the draw in the attached figure N 3

<u>case 4)</u> For x=30 units

substitute in the equation 1

x*y=64      

y=64/x

y=64/30

y=\frac{32}{15} =2\frac{2}{15} \ units

the dimensions of the rectangle are 30 units x 2 (2/15) units

see the draw in the attached figure N 4

<u>case 5)</u> For x=40 units

substitute in the equation 1

x*y=64    

y=64/x

y=64/40

y=1.60\ units

the dimensions of the rectangle are 40 units x 1.60 units

see the draw in the attached figure N 5

<u>case 6)</u> For x=60 units

substitute in the equation 1

x*y=64    

y=64/x

y=64/60

y=\frac{16}{15} =1\frac{1}{15} \ units

the dimensions of the rectangle are 60 units x 1 (1/15) units

see the draw in the attached figure N 6

3 0
3 years ago
When 200 gallons of oil were removed from a tank, the volume of oil left in the tank was 3/7 of the tank's capacity. what was th
ki77a [65]

Answer:

Step-by-step explanation:

"When 200 gallons of oil were removed from a tank" algebraically looks like this:

V - 200.

"...the volume of oil left in the tank was 3/7 of the tank's capacity" algebraically looks like this:

3/7(V)

Therefore, the equation is

V - 200 = 3/7(V)

Begin by multiplying both sides by 7:

7(V - 200) = 3V and

7V - 1400 = 3V so

-1400 = -4V so

V = 350 gallons

That's if the volume of the oil in the tank was 3/7 of the tank's capacity.

For the other part of the problem, we set up the equation almost the same, except the 3/7 is a 1/2:

V - 200 = 1/2(V)

Multiplying both sides by 2 gives you

2(V - 200) = V and

2V - 400 = V so

-400 = -V so

V = 400

7 0
3 years ago
Find the measure of angle t
natima [27]

\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }

\large\underline{  \boxed{ \sf{✰\:Important\: point's }}}

  • ➢Given two lines are intersecting lines
  • ➢ as it's clearly known when two or more lines meet each other at a specific points is said to be as intersecting lines nd they must be having a common point
  • ➢Here angle t and angle 120⁰ forms adjacent angles
  • and sum sum of adjacent angles is 180⁰

{ \rule{70mm}{2.9pt}}

\underline{  \boxed{ \sf{✵\: let's\: solve\:✵}}}

\sf ➛\angle \: 120 \degree + \angle \:t  = 180\degree \\   \sf ➛\angle  \:t = 180 \degree -   \angle \:120 \degree \\   \sf ➛\angle \: t =  \:60 \degree

{ \rule{70mm}{2.9pt}}

\boxed{✛\underline{  \boxed{ \sf{ \: \angle \: t = 60 \degree  \: }}}✛}

Hope it helps !

5 0
2 years ago
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