Given:
Big cone : diameter = 12 cm ; height = 18 cm ; base = 14 cm
Small cone: diameter = 12 cm ; height = 6 cm ; base = 14 cm
Volume of a cone-shaped container = π r² h/3
Big cone:
V = 3.14 * (6cm)² * 18cm/3
V = 3.14 * 36cm² * 6cm
<span>V = 678.24 cm³
</span>Small cone:
V = 3.14 * (6cm)² * 6cm/3
V = 3.14 * 36cm² * 2cm
<span>V = 226.08 cm³
</span>Big cone - small cone = volume of water
678.24 cm³ - 226.08 cm³ = 452.16 cm³
I think that the answer is .00004
Y = 1/3 x - 10 . . . (1)
2x + y = 4 . . . . . (2)
Putting (1) into (2) gives
2x + 1/3 x - 10 = 4
7/3 x = 4 + 10 = 14
x = (3 x 14)/7 = 3 x 2 = 6
x = 6
From (1), y = 1/3 (6) - 10 = 2 - 10 = -8
y = -8
-5 +25-10m ≥ 60
20-10m ≥60
-10m ≥40
m ≤ -4 note flip equality sign because diving by a negative number
5 (4n+5)-4 ≤ 101
20n +25-4 ≤101
20 n +21 ≤ 101
20n ≤ 80
n ≤ 4
3(4-5p) -4 ≥ -67
12 -15p-4 ≥ -67
8 -15p ≥ -67
-15p ≥ -75
p ≤ 15 also flipped sign
-3(5m+2). < 54
-15m -6 &It 54
-15 m &Lt 60
m < -4
( I don’t know what sign < means I am assuming less than ? Just put the appropriate sign )
3x -4 (-5x+3) ≥ 57
3x +20x -12 ≥ 57
23x -12 ≥ 57
23x ≥ 69
x ≥ 3
Answer: What I do not know is the measurement of the third side.
Step-by-step explanation: The first thing to explain over the phone is that this is a scalene triangle. Two sides have been identified, and two angles have also been identified. For an equilateral triangle, all three sides and all three angles must be equal. For an isosceles triangle, two sides and two angles must be equal. In this diagram, two angles have been given as 88° and 50°. The third angle be derived as
88 + 50 + X = 180
138 + X = 180
X = 42.
If all three angles are now given as 88, 50 and 42 then the triangle is definitely a scalene triangle, and this would surely mean the measurement of the third side would be different from the other two. And to calculate the third side would require the application of the Sine Rule, which would in itself require the use of a calculator and careful mathematical calculations.
