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Lubov Fominskaja [6]
3 years ago
10

Simplify the expression

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
7 0

Answer:

-88

Step-by-step explanation:

If a=2, we can say that -a^{2} would be -4.

Secondly, if a=2 and b=-6 we can assume that 4ab would become -48.

Finally, if b=-6 we can say that -b^{2} would become -36.

Adding all of those up gives you -88, your answer.

KIM [24]3 years ago
3 0

Answer:

-88

Step-by-step explanation:

Replace the variable a with 2

↓↓↓

-(2)^2+4(2)*b-b^2

Replace the variable b with −6

-(2)^2+4(2)*(-6)-(-6)^2

Raise 2 to the power of 2

-1*4+4(2)*(-6)-(-6)^2

Multiply −1 by 4

-4+4(2)*(-6)-(-6)^2

Multiply 4 by 2

-4+8*-6-(-6)^2

Multiply 8 by −6

-4-48-(-6)^2

Raise −6 to the power of 2

-4-48-1*36

Multiply −1 by 36

-4-48-36

basic subtraction follows this

and we are left with an answer of -88

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6 0
2 years ago
Assume that round widgets from a manufacturing process have diameters that are normally distributed with mean 135.75 centimeters
Cloud [144]

Answer:

b. 99 out of 100.

Step-by-step explanation:

We solve for this using z score formula

z-score formula is given as:

z = (x - μ)/σ

where

x is the raw score

μ is the population mean

σ is the population standard deviation.

a) x = 129cm, μ = 135.75cm, σ = 1.85cm

z = (129- 135.75)/1.85

z = -3.64865

Finding the Probability value of the z score from the z table:

P(x = 129) = P(z = -3.64865)

= 0.00013181

b) x = 143 cm, μ = 135.75cm, σ = 1.85cm

z = (143- 135.75)/1.85

z = 3.91892

Finding the Probability value of the z score from the z table:

P(x = 143) = P(z = 3.91892)

= 0.99996

The chances that a randomly selected widget has diameter between 129 centimeters and 143centimeters

= P(x = 143) - P(x = 129)

= P(z = 3.91892) - P(z = -3.64865)

= 0.99996 - 0.00013181

= 0.99982819

Converting to percentage

= 0.99982819 × 100

= 99.982819%

Therefore, option b. 99 out of 100 is the correct answer

8 0
3 years ago
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