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Sidana [21]
3 years ago
12

The histogram shows how many jogging runs Maria made for each interval of miles. A histogram titled Maria's Monthly Jogging has

miles run on the x-axis and number of runs on the y-axis. 1 to 1.99 miles is 2 runs; 2 to 2.99 miles is 5 runs; 3 to 3.99 miles is 5 runs; 4 to 4.99 miles is 3 runs; 5 to 5.99 miles is 4 runs; 6 to 6.99 is 7 runs; 7 to 7.99 miles is 4 runs. Which statement about the histogram is true? The majority of Maria’s runs were short, two-mile runs. More than half Maria’s runs were less than five miles each. The majority of Maria’s runs were between five and six miles. At least 15 of Maria’s runs were more than four miles each.
Mathematics
2 answers:
earnstyle [38]3 years ago
6 0

Answer:at least 15 of maria's runs were more then four miles each

Step-by-step explanation:

HACTEHA [7]3 years ago
6 0

Answer:

15

Step-by-step explanation:

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The number of miles Ford trucks can go on one tank of gas is normally distributed with a mean of 350 miles and a standard deviat
kati45 [8]

Answer:

The probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.

Step-by-step explanation:

Let <em>X</em> = the number of miles Ford trucks can go on one tank of gas.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 350 miles and standard deviation, <em>σ</em> = 10 miles.

If the Ford truck runs out of gas before it has gone 325 miles it implies that the truck has traveled less than 325 miles.

Compute the value of P (X < 325) as follows:

P(X

Thus, the probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.

7 0
3 years ago
Help please now help dont be childish will banned ​
belka [17]

Answer:

X, process, y

-2, 3(-2), -6

-1, 3(-1), -3

0, 3(0), 0

1, 3(1), 3

2, 3(2), 6

X = -2, -1, 0, 1, 2,

Y = -6, -3, 0, -3, -6

Step-by-step explanation:

Coordinates for the graph: (-2,-6), (-1,-3), (0,0), (1,3), (2,6)

Graph is the image I added onto this.

Solving for Y below:

3(-2)= -6

3(-1)= -3

3(0)= 0

3(1)= 3

3(2)= 6

Hope this helps.

5 0
3 years ago
There are 92,746 seats available for fans at UGA's Sanford Stadium. Auburn University's Jordan-Hare Stadium has seating for 87,4
Anvisha [2.4K]

Given :

Number of seats at UGA's Sanford Stadium, n_1 = 92,746 .

Number of seats at Auburn University's Jordan-Hare Stadium, n_2=87,451 .

To Find :

How many more seats are there at UGA's stadium.

Solution :

Extra seats at UGA's stadium = seats at UGA's Sanford Stadium - seats at    

                                                     Auburn University's Jordan-Hare Stadium

= 92,746 - 87,451

= 5295

Hence, this is the required solution.

4 0
3 years ago
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gizmo_the_mogwai [7]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
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mamaluj [8]

Answer: .0142%

Step-by-step explanation:

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3 years ago
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