A program to demonstrate circular linked list with operations using pointers is:
struct Node *addToEmpty(struct Node *last, int data)
{
// This function is only for empty list
if (last != NULL)
return last;
// Creating a node dynamically.
struct Node *temp =
(struct Node*)malloc(sizeof(struct Node));
// Assigning the data.
temp -> data = data;
last = temp;
// Note : list was empty. We link single node
// to itself.
temp -> next = last;
return last;
}
<h3>What is a Circular Linked List?</h3>
This refers to the type of linked list in which the first and the last nodes are also joined together other to form a circle
Read more about circular linked list here:
brainly.com/question/12974434
#SPJ1
Answer: The how-to statements
Explanation:
The mission statement is simply a short summary of the purpose of a company. It is the guideline on how a company will operate. The mission statement states the reason for the existence of a company, products sold or service rendered and the company's goals.
The mission statement should be brief but comprehensive, consist of simple words and describe the “who, what, and where” of the organization.
Therefore, the incorrect option based on the explanation above is "The how-to statements". This shouldn't be part of the mission statement.
Answer:
otp
Explanation:
don't know bro ask to your teacher
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
