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Reptile [31]
3 years ago
13

A good CRM should Integrate marketing, sales, and customer support activities measuring and evaluating the process of knowledge

acquisition and sharing.
Computers and Technology
1 answer:
ivolga24 [154]3 years ago
3 0

The correct answer to this open question is the following.

Unfortunately, you forgot to include a question. Here, we just have a statement.

What is your question? What do you want to know?

If this is a true or false question, the answer is "true."

It is true that a good CRM should integrate marketing, sales, and customer support activities measuring and evaluating the process of knowledge acquisition and sharing.

The reason is that effective investment in Customer Relationship Management (CRM) should be able to operate efficientñy with these management aspects in order to increase the productivity and efficiency of the company.

A good CRM has to facilitate the operations of a company, improving time management and people's activities that can produce better results accomplishing the companies goals and fulfilling the key performing indicators (KPI)

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Please please help I don’t understand this please.
PIT_PIT [208]

Answer:

first the class declaration (the bit with class player)

then the object creation (myPlayer = player())

then assigning a value to a property (myPlayer.life=4)

Explanation:

You have to declare the class before you can use it.

You have to create an object before you can access its members.

Unclear why in the exercise second and first are swapped...?

3 0
3 years ago
I need an answer fast !!! (APEX)
lana [24]
Your answer is B)<span>The Intel 4004</span>
3 0
3 years ago
Create a function that will perform linear interpolation from a set of measured data stored in a list or array. The function sho
wel

Answer:

This question is incomplete, here is the complete question:

Python

a) You should create a function that will perform linear interpolation from a set of measured data. The function should take as input a list of values at which samples were taken, and then another list giving the measurements (you can assume each measurement is a single value) at those values. It should also take in a query value, and should give the best estimate it can of the value at that query. Be sure to handle values that are outside of the range, by extrapolating. You should write a program that allows you to test your function by reading the lists from a file where each line of the file is a pair of numbers separated by spaces: the value where the sample was taken, and the measurement at that value. Your program should ask the user for the name of the file and for a query value. Important: The two lists will correspond to each other: i.e. for the i-th value in the first list, the measurement will be the i-th element of the second list (these are called parallel lists or arrays). But, you should not assume that the input values are in increasing/decreasing order. That is, the values in the first list can be in any random ordering, not necessarily from smallest to largest or largest to smallest. You will have to account for this in your program, and there is more than one way to do so. You should discuss what options you can think of to handle the data arriving in any order like that, and decide what you think the best option for handling it is.

Explanation:

from __future__ import division

from cStringIO import StringIO

import numpy as np

from scipy.interpolate import RectBivariateSpline

np.set_printoptions( 1, threshold=100, edgeitems=10, suppress=True )

   # a file inline, for testing --

myfile = StringIO( """

# T P1 P2 P3 P4

0,   80,100,150,200

75, 400,405,415,430

100, 450,456,467,483

150, 500,507,519,536

200, 550,558,571,589

""" )

   # file -> numpy array --

   # (all rows must have the same number of columns)

TPU = np.loadtxt( myfile, delimiter="," )

P = TPU[0,1:] # top row

T = TPU[ 1:,0] # left col

U = TPU[1:,1:] # 4 x 4, 400 .. 589

print "T:", T

print "P:", P

print "U:", U

interpolator = RectBivariateSpline( T, P, U, kx=1, ky=1 ) # 1 bilinear, 3 spline

   # try some t, p --

for t, p in (

   (75, 80),

   (75, 200),

   (87.5, 90),

   (200, 80),

   (200, 90),

   ):

   u = interpolator( t, p )

   print "t %5.1f p %5.1f -> u %5.1f" % (t, p, u)

8 0
3 years ago
Why are coders using encoder software? What are their advantages and disadvantages? And when might a coder need to use the codin
IrinaVladis [17]
<span>Coders using encoder software:
To enhance their productivity</span><span>
Speed and Efficiency
</span><span>Accuracy and consistency
</span>
Encoding is done to reduce the number of bit to be transmitted and save bandwidth .can be fairly complex and contain some delicate parts. This makes them less tolerant of mechanical abuse and restricts their allowable temperature.

<span>including increased productivity, accuracy, and efficiency in coding and the consistent application of coding rules. However, there is a cost to the software, but savings can be seen in other areas.</span>

7 0
2 years ago
Freeeee BRAINLIESTHBJHBJHB
andre [41]

Answer:A lot of people cry when they cut an onion. The trick is not to form an emotional bond.lol

4 0
3 years ago
Read 2 more answers
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