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MaRussiya [10]
2 years ago
11

How do we find what x is in this problem

Mathematics
2 answers:
Alexxx [7]2 years ago
6 0
Set The Numbers On The Side Equal To The Equation. Use Inverse Operation And Divide Since The X Is Used In Multiplication.
kykrilka [37]2 years ago
3 0
Ok so since x is the unkown variable we would need to isolate the variable. That means do the opposite operation. So we divide 2 by 2 because thats the coefficient. Then what you do is do the same thing on the other side,divide 1 by 2 to get your answer. your answer would be x=whatever your answer is.
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Which angle description represents an angle that is greater than ninety degrees?
lukranit [14]
The Awnser is c obtuse angle
5 0
3 years ago
How to do this question plz ​
sergeinik [125]

Answer:

The answer is yes.

Step-by-step explanation:

All you have to do is substitute the y, which is 5, and the x, which is 2, into the equation. When you solve it the answer in the end will be 5=5, which means that point (2,5) does line on that line.

3 0
3 years ago
What does 7m- m equal
Norma-Jean [14]
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4 0
11 months ago
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0
3 years ago
Please help ASAP and if you don't see the picture tell me.
Art [367]
I cant see a picture
7 0
2 years ago
Read 2 more answers
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