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Julli [10]
3 years ago
12

Someone help with this Given a1 = 25 and d = -2, what is the 8th term?

Mathematics
1 answer:
german3 years ago
3 0

Answer:

a₈ = 11

Step-by-step explanation:

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 25 and d = - 2, then

a₈ = 25 + (7 × - 2)

   = 25 - 14

   = 11

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0.68 = 0.6 + ___ = ____ x 0.1 + 8 x ____
8_murik_8 [283]

0.68 = 0.6 + .08 = 6 x 0.1 + 8 x .01

They should all equal  0.68  :)

5 0
4 years ago
Find the equation of the line passing through the point (–1, 0) and parallel to the line y = –1∕2x + 3∕7
PilotLPTM [1.2K]

Answer:

y = -1/2x - 1/2

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step 1: Define

y = -1/2x + 3/7

Point (-1, 0)

Step 2: Find parallel line

<em>Parallel lines have the same slope as the original but different y-intercepts.</em>

<em>m</em> = -1/2

y = -1/2x + b

0 = -1/2(-1) + b

0 = 1/2 + b

b = -1/2

Step 3: Write parallel line

y = -1/2x - 1/2

7 0
4 years ago
Algebra 1 Solve number 10 !!!
tangare [24]

Answer:

0.06x + 0.15y = 69.84

x = (69.84 - 0.15y) / 0.06

y = (69.84 - 0.06x) / 0.15

x + y = 852

((69.84 - 0.15y) / 0.06) + y = 852

y = ?

(I'm not trying to give you the answer but guide you how to do it)

8 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
4 years ago
Solve.<br><br> 10 · w = 90<br><br> w = ______
Ratling [72]

Answer:

80

Step-by-step explanation:

10- w = 90

w = 90 -10

w = 80

5 0
3 years ago
Read 2 more answers
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