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melisa1 [442]
3 years ago
12

Can someone help 10 points

Mathematics
1 answer:
ser-zykov [4K]3 years ago
7 0

Answer:

The volume of this rectangular prism is 72 cubic units. We multiply 6*4*3 to get 72.

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Ineed help help me please
melamori03 [73]
The symbol ₁₂P₉ represents the permutations of 9  quantities out of 12.
By definition,
_{12}P_{9} =  \frac{12!}{(12-9)!} = \frac{12!}{3!}

From the calculator,
12! = 479,001,600
3! = 6

Therefore
₁₂P₉ = 479001600/6 = 79,833,600

Answer: 79,833,600
8 0
4 years ago
What is the sum of 27 +48
soldi70 [24.7K]
The correct solution is 75. 
4 0
4 years ago
Read 2 more answers
A standard deck of 52 cards consists of 4 suits (hearts, diamonds, clubs, and spades). Each suit includes cards numbered 2 throu
Margaret [11]
B hope this helps you on your test
6 0
3 years ago
Read 2 more answers
What is 6 divied 192 please show work
suter [353]
The problem presented with the word used as "divied" is very tricky and misleading to the point that it might create an understanding.

So we will approach this is in two ways.

If this was meant to be "divided by" then it would look like this:
6 / 192

If this was meant to be "divided to" then it would look like this:
192 / 6

Let us first solve for the first possible problem:
6 / 192 = ?
0.0312

0.0312 would be the answer.

Let us then solve for the second possible problem:
192 / 6 = ?
32 = ?

32 would be the answer.

So 0.0312 and 32 would be two possible answers to this problem.
4 0
3 years ago
Read 2 more answers
Fred and Frank play a game. Fred picks an even number X and asks Frank to add all even numbers between 0 and X (inclusive) as fa
TiliK225 [7]

Answer:

The even numbers between 0 and X represents an arithmetic sequence with a common difference of 2

The rule of arithmetic sequence = a + d(n - 1)

Where a is the first term and n is the number of terms

So, for the even numbers between 0 and X

The first term = a = 0

d = 2

So, we need to find n at the last term which is X

∴ X = 0 + 2 ( n -1 )

∴ n - 1 = X/2

∴ n = X/2 + 1

The sum of the arithmetic sequence = (n/2) × (2a + (n−1)d)

Substitute with a and d and X

So, the sum = (n/2) * (2*0 + (n−1)*2)

                   = (n/2) * ((n−1)*2)

                   = n(n-1)

                   = (X/2 + 1) * (X/2)

                   = X/2 by (X/2 + 1)

So, The quick way to add all even numbers between 0 and X always works.

8 0
4 years ago
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