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2 years ago

What is thirty divided by ten

Mathematics

2 answers:

ivanzaharov [21]2 years ago

3 0

Answer:

It is three.................

kolezko [41]2 years ago

3 0

30 ÷ 3 = 3

Hope this helps :)

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A student obtain 85 ,90,95,100and 75 in his maths test (1). What is the average of his test grades?

netineya [11]

Answer:

89.

Step-by-step explanation:

There are 5 scores.

So the Average = (85 + 90+95+100+ 75)/5

= 445/5

= 89.

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2 years ago

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How do you solve for a and b?

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You need to isolate b on one side of the equation then divide both side by h finally move b on the other side of the equation by subtracting it from both sides of the equation and then you have what b equals to

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On a recent homework assignment, Eli needed to solve the equation

tamaranim1 [39]

Answer:

A - the real answer is 7

Step-by-step explanation:

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B) not sure - possibly wrote the negative sign as a mistake

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3 years ago

1. Graph the linear function f(x) = -2x + 1

anyanavicka [17]

Answer: The slope is -2 and the y-intercept is (0,1)

Step-by-step explanation:

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1 year ago

Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,

kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

$V_{flask}=V_{sphere}+V_{cylinder}.$

Use following formulas to determine volumes of sphere and cylinder:

$V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,$

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

$V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;$
$V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;$
$V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.$

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

$V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.$

Then

$\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.$

Answer 2: correct choice is D.

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3 years ago

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